Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

yashar806

  • one year ago

see attachment

  • This Question is Closed
  1. yashar806
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  2. satellite73
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    3 are brown and so evidently 6 are not brown use the binomial \[\binom{9}{3}(.21)^3(.79)^6\]

  3. dhruv_khatkar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i think you can use the formula (n x) . p^x . q ^(n-x)

  4. yashar806
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what about the second one?

  5. yashar806
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sorry third one

  6. kropot72
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    For the third one you use the fact that the binomial distribution can be approximated by the normal distribution when n is large and p is neither small nor near 1.\[\mu=np=175\times 0.21\] \[\sigma=\sqrt{np(1-p)}=\sqrt{175\times 0.21\times 0.79}\] Then you find the required probability by means of a standard normal distribution table.

  7. yashar806
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh, fourth one?

  8. kropot72
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Basically you use the same method for the fourth one as for the third, but change the values of n and p accordingly.

  9. kropot72
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You need to find one value of z-score for the third one and two values of z-score for the fourth.

  10. yashar806
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    because there two values 17% and 24%

  11. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.