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koli123able

  • 2 years ago

Prove: cotx+tanx=cotx * sec^2x

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  1. hartnn
    • 2 years ago
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    write sec^2x = .... ?

  2. koli123able
    • 2 years ago
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    1/cos^2x

  3. hartnn
    • 2 years ago
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    1+ tan^2 x ?

  4. koli123able
    • 2 years ago
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    sec^2x

  5. hartnn
    • 2 years ago
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    then you can use directly here, tan x cot x =1

  6. klimenkov
    • 2 years ago
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    All you need to know is the definition of \(\tan x, \cot x, \sec x\) and how to work with fractions.

  7. hartnn
    • 2 years ago
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    yes, so i said to replace sec^2 x by 1+tan^2x

  8. hartnn
    • 2 years ago
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    can be solved without involving fractions ... :)

  9. hartnn
    • 2 years ago
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    @koli123able did you try ?

  10. koli123able
    • 2 years ago
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    which side to choose?

  11. hartnn
    • 2 years ago
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    right ...?

  12. hartnn
    • 2 years ago
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    cotx * sec^2x=cotx * (1+tan^2 x) =..... ?

  13. koli123able
    • 2 years ago
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    cotx+ cotx tan^2x

  14. KAOS|abdullah
    • 2 years ago
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    cotx tanx becomes 1

  15. hartnn
    • 2 years ago
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    cotx+ cotx tan^2x = cot x + tan x (cot x tan x)

  16. koli123able
    • 2 years ago
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    is that an identity cot x tanx =1 ??

  17. hartnn
    • 2 years ago
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    absolutely. tan x = 1/cot x so, tan x cot x =1

  18. noureddine92
    • 2 years ago
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    cosx/sinx =sinx/cosx

  19. noureddine92
    • 2 years ago
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    cos^2x + sin^2x / cosx sinx

  20. noureddine92
    • 2 years ago
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    1/cosxsinx

  21. noureddine92
    • 2 years ago
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    cscx+secx

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