anonymous
  • anonymous
Prove: cotx+tanx=cotx * sec^2x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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hartnn
  • hartnn
write sec^2x = .... ?
anonymous
  • anonymous
1/cos^2x
hartnn
  • hartnn
1+ tan^2 x ?

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More answers

anonymous
  • anonymous
sec^2x
hartnn
  • hartnn
then you can use directly here, tan x cot x =1
klimenkov
  • klimenkov
All you need to know is the definition of \(\tan x, \cot x, \sec x\) and how to work with fractions.
hartnn
  • hartnn
yes, so i said to replace sec^2 x by 1+tan^2x
hartnn
  • hartnn
can be solved without involving fractions ... :)
hartnn
  • hartnn
@koli123able did you try ?
anonymous
  • anonymous
which side to choose?
hartnn
  • hartnn
right ...?
hartnn
  • hartnn
cotx * sec^2x=cotx * (1+tan^2 x) =..... ?
anonymous
  • anonymous
cotx+ cotx tan^2x
anonymous
  • anonymous
cotx tanx becomes 1
hartnn
  • hartnn
cotx+ cotx tan^2x = cot x + tan x (cot x tan x)
anonymous
  • anonymous
is that an identity cot x tanx =1 ??
hartnn
  • hartnn
absolutely. tan x = 1/cot x so, tan x cot x =1
anonymous
  • anonymous
cosx/sinx =sinx/cosx
anonymous
  • anonymous
cos^2x + sin^2x / cosx sinx
anonymous
  • anonymous
1/cosxsinx
anonymous
  • anonymous
cscx+secx

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