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DHASHNIBest ResponseYou've already chosen the best response.1
so wat shud we do with it ?
 one year ago

brillemandBest ResponseYou've already chosen the best response.0
i'd like to know how to brake down this equation.
 one year ago

DHASHNIBest ResponseYou've already chosen the best response.1
(a + b + c)(a + b + c)(a + b + c) (a² + ab + ac + ab + b² + bc + ac + bc + c²)(a + b + c) (a² + 2ab + 2ac + b² + 2bc + c²)(a + b + c) a³ + a²b + a²c + 2a²b + 2ab² + 2abc + 2a²c + 2abc + 2ac² + ab² + b³ + b²c + 2abc + 2b²c + 2bc² + ac² + bc² + c³ a³ + 3a²b + 3a²c + 3ab² + 6abc + 3ac² + b³ + 3b²c + 3bc² + c³
 one year ago

DHASHNIBest ResponseYou've already chosen the best response.1
here a =x b=y and c=1
 one year ago

brillemandBest ResponseYou've already chosen the best response.0
Thank you very much kind sir
 one year ago
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