Here's the question you clicked on:
brillemand
(x² + y² -1) ³ -x²y³ =0
so wat shud we do with it ?
i'd like to know how to brake down this equation.
(a + b + c)(a + b + c)(a + b + c) (a² + ab + ac + ab + b² + bc + ac + bc + c²)(a + b + c) (a² + 2ab + 2ac + b² + 2bc + c²)(a + b + c) a³ + a²b + a²c + 2a²b + 2ab² + 2abc + 2a²c + 2abc + 2ac² + ab² + b³ + b²c + 2abc + 2b²c + 2bc² + ac² + bc² + c³ a³ + 3a²b + 3a²c + 3ab² + 6abc + 3ac² + b³ + 3b²c + 3bc² + c³
Thank you very much kind sir