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krallen95

  • 3 years ago

Which point is on the circle described by (x - 2)2 + (y + 3)2 = 4?

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  1. DHASHNI
    • 3 years ago
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    |dw:1363534727565:dw|

  2. DHASHNI
    • 3 years ago
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    when x=0 y= -3

  3. pooja195
    • 3 years ago
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    x-a)^2+(y-b)^2=R^2 is the point M(a,b) and the radius of this circle is R (x – 2)^2 + (y + 3)^2 = 17 the center of this circle is A(2,-3)and the center of the circle (x – 5)^2 + y^2 = 32 is B(5,0) The line (D): y=ax+b which passes through A and B is such that A belongs to (D) ==> -3=a(2)+b=2a+b ==> b=-2a-3(*) B belongs to (D) ==> 0=a(5)+b=5a+b ==>b=-5a(**) (*) and (**) lead to -5a=-2a-3 ==> 5a-2a-3=0 ==> 3a-3=0 ==>3a=3 ==> a=3/3=1 ==> a=1 From (**) b=-5a=-5(1)=-5 Finally the equation of (D) is y=x-5

  4. Directrix
    • 3 years ago
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    This (when x=0 y= -3) is the y-intercept of the circle.

  5. Vinayakvivek
    • 3 years ago
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    |dw:1363582218886:dw|

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