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Which point is on the circle described by (x - 2)2 + (y + 3)2 = 4?

Mathematics
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when x=0 y= -3
x-a)^2+(y-b)^2=R^2 is the point M(a,b) and the radius of this circle is R (x – 2)^2 + (y + 3)^2 = 17 the center of this circle is A(2,-3)and the center of the circle (x – 5)^2 + y^2 = 32 is B(5,0) The line (D): y=ax+b which passes through A and B is such that A belongs to (D) ==> -3=a(2)+b=2a+b ==> b=-2a-3(*) B belongs to (D) ==> 0=a(5)+b=5a+b ==>b=-5a(**) (*) and (**) lead to -5a=-2a-3 ==> 5a-2a-3=0 ==> 3a-3=0 ==>3a=3 ==> a=3/3=1 ==> a=1 From (**) b=-5a=-5(1)=-5 Finally the equation of (D) is y=x-5

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This (when x=0 y= -3) is the y-intercept of the circle.
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