A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
Show that the function sinx+cosx is of period 2pi. Also prove that sinx+cosx=sqrt(2)sin(x+pi/4)
 one year ago
Show that the function sinx+cosx is of period 2pi. Also prove that sinx+cosx=sqrt(2)sin(x+pi/4)

This Question is Closed

yashar806
 one year ago
Best ResponseYou've already chosen the best response.1hi satellite help me after this

goformit100
 one year ago
Best ResponseYou've already chosen the best response.0i think it is C.B.S.E. Question

koli123able
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt2\sin(x+\frac{ \pi }{ 4 })\]

koli123able
 one year ago
Best ResponseYou've already chosen the best response.0what does C.B.S.E means ?

koli123able
 one year ago
Best ResponseYou've already chosen the best response.0sinx cos pi/4 + cosx sin pi/4 what's next?

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0it is a consequence of the "addition angle" formula the general case is \[a\sin(x)+b\cos(x)=\sqrt{a^2+b^2}\sin(x+\theta)\] and a succinct explanation is in the attachment

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0this requires putting into the form asin(x) + bcos(x) = Rsin(x + m) \[R = \sqrt{a^2 + b^2}\] and \[m = \tan^{1}(\frac{a}{b})\] so\[R = \sqrt{1^2 + 1^2 } = \sqrt{2}\] \[m = \tan^{1}(\frac{1}{1}) = \frac{\pi}{4}\] so you get \[\sqrt{2}\sin(x + \frac{\pi}{4})\]
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.