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anonymous
 3 years ago
solve system of equation:
x+y=1
yz=4
2x+y+5z=38
anonymous
 3 years ago
solve system of equation: x+y=1 yz=4 2x+y+5z=38

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cyber405
 3 years ago
Best ResponseYou've already chosen the best response.0You can use y4=z instead of z in the third equation... Do you know rest of the solution...?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0plug it into your calculator!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i got 13,14, and 10 or 10 and something still not adding up right

cyber405
 3 years ago
Best ResponseYou've already chosen the best response.0What's the problem...?

cyber405
 3 years ago
Best ResponseYou've already chosen the best response.0y  z = 4 > z = y  4 x + y = 1 > x = y1 then plug these into third one... 2x + y + 5z = 38 > 2(y1) + y + 5(y4) = 38 .... 2y2+y+5y20=38 > 4y=16 y=... then plug y in other equations to find x and z...
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