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solve system of equation:
x+y=1
yz=4
2x+y+5z=38
i need step by step help please?
 one year ago
 one year ago
solve system of equation: x+y=1 yz=4 2x+y+5z=38 i need step by step help please?
 one year ago
 one year ago

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Kanwar245Best ResponseYou've already chosen the best response.1
step1; multiply equation 1 with 1
 one year ago

Kanwar245Best ResponseYou've already chosen the best response.1
step2; add equation 1 and equation 2
 one year ago

Kanwar245Best ResponseYou've already chosen the best response.1
you'll get an equation in terms of x and z
 one year ago

krissywattsBest ResponseYou've already chosen the best response.0
so my finale for that would be xz=4 correct?
 one year ago

krissywattsBest ResponseYou've already chosen the best response.0
no what is the next step?
 one year ago

Kanwar245Best ResponseYou've already chosen the best response.1
also you can rewrite last equation as 2x + 4 + z + 5z = 38
 one year ago

Kanwar245Best ResponseYou've already chosen the best response.1
2x + 6z = 42 or x + 2z = 31
 one year ago

Kanwar245Best ResponseYou've already chosen the best response.1
and you have x z = 5
 one year ago

Kanwar245Best ResponseYou've already chosen the best response.1
solve these two equations
 one year ago

agent0smithBest ResponseYou've already chosen the best response.0
Assuming Kanwar245 is correct, z = 26 x = 31 to find y, use these values in one of these equations to find y: x+y=1 yz=4 2x+y+5z=38 from the first, x+y=1, so \[\large y = 1  x = 1  (31) = 30 \]. or use the second, yz=4, so \[\large y= 4+z = 4+26 = 30\] or use the third, 2x+y+5z=38, so \[y = 38 2x 5z = 38 2(31)5(26) = 106\] This doesn't agree with the other value for y of 30, so it's possible there's a mistake somewhere.
 one year ago
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