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 one year ago
solve system of equation:
x+y=1
yz=4
2x+y+5z=38
i need step by step help please?
 one year ago
solve system of equation: x+y=1 yz=4 2x+y+5z=38 i need step by step help please?

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Kanwar245
 one year ago
Best ResponseYou've already chosen the best response.1step1; multiply equation 1 with 1

Kanwar245
 one year ago
Best ResponseYou've already chosen the best response.1step2; add equation 1 and equation 2

Kanwar245
 one year ago
Best ResponseYou've already chosen the best response.1you'll get an equation in terms of x and z

krissywatts
 one year ago
Best ResponseYou've already chosen the best response.0so my finale for that would be xz=4 correct?

krissywatts
 one year ago
Best ResponseYou've already chosen the best response.0no what is the next step?

Kanwar245
 one year ago
Best ResponseYou've already chosen the best response.1also you can rewrite last equation as 2x + 4 + z + 5z = 38

Kanwar245
 one year ago
Best ResponseYou've already chosen the best response.12x + 6z = 42 or x + 2z = 31

Kanwar245
 one year ago
Best ResponseYou've already chosen the best response.1and you have x z = 5

Kanwar245
 one year ago
Best ResponseYou've already chosen the best response.1solve these two equations

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.0Assuming Kanwar245 is correct, z = 26 x = 31 to find y, use these values in one of these equations to find y: x+y=1 yz=4 2x+y+5z=38 from the first, x+y=1, so \[\large y = 1  x = 1  (31) = 30 \]. or use the second, yz=4, so \[\large y= 4+z = 4+26 = 30\] or use the third, 2x+y+5z=38, so \[y = 38 2x 5z = 38 2(31)5(26) = 106\] This doesn't agree with the other value for y of 30, so it's possible there's a mistake somewhere.
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