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krissywatts

  • one year ago

solve system of equation: x+y=-1 y-z=4 2x+y+5z=-38 i need step by step help please?

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  1. Kanwar245
    • one year ago
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    step1; multiply equation 1 with -1

  2. Kanwar245
    • one year ago
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    step2; add equation 1 and equation 2

  3. Kanwar245
    • one year ago
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    you'll get an equation in terms of x and z

  4. krissywatts
    • one year ago
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    so my finale for that would be -x-z=4 correct?

  5. krissywatts
    • one year ago
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    @Kanwar245

  6. Kanwar245
    • one year ago
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    -x - z = 5

  7. krissywatts
    • one year ago
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    yes sorry

  8. krissywatts
    • one year ago
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    no what is the next step?

  9. krissywatts
    • one year ago
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    now*

  10. Kanwar245
    • one year ago
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    also you can rewrite last equation as 2x + 4 + z + 5z = -38

  11. Kanwar245
    • one year ago
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    2x + 6z = -42 or x + 2z = 31

  12. Kanwar245
    • one year ago
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    and you have -x -z = 5

  13. Kanwar245
    • one year ago
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    solve these two equations

  14. krissywatts
    • one year ago
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    okay

  15. Kanwar245
    • one year ago
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    you get z = 26

  16. Kanwar245
    • one year ago
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    x = -31

  17. krissywatts
    • one year ago
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    is y 30?

  18. krissywatts
    • one year ago
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    @Kanwar245

  19. krissywatts
    • one year ago
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    @campbell_st

  20. krissywatts
    • one year ago
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    @agent0smith

  21. agent0smith
    • one year ago
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    Assuming Kanwar245 is correct, z = 26 x = -31 to find y, use these values in one of these equations to find y: x+y=-1 y-z=4 2x+y+5z=-38 from the first, x+y=-1, so \[\large y = -1 - x = -1 - (-31) = 30 \]. or use the second, y-z=4, so \[\large y= 4+z = 4+26 = 30\] or use the third, 2x+y+5z=-38, so \[y = -38 -2x -5z = -38 -2(-31)-5(26) = -106\] This doesn't agree with the other value for y of 30, so it's possible there's a mistake somewhere.

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