anonymous
  • anonymous
solve system of equation: x+y=-1 y-z=4 2x+y+5z=-38 i need step by step help please?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
step1; multiply equation 1 with -1
anonymous
  • anonymous
step2; add equation 1 and equation 2
anonymous
  • anonymous
you'll get an equation in terms of x and z

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anonymous
  • anonymous
so my finale for that would be -x-z=4 correct?
anonymous
  • anonymous
anonymous
  • anonymous
-x - z = 5
anonymous
  • anonymous
yes sorry
anonymous
  • anonymous
no what is the next step?
anonymous
  • anonymous
now*
anonymous
  • anonymous
also you can rewrite last equation as 2x + 4 + z + 5z = -38
anonymous
  • anonymous
2x + 6z = -42 or x + 2z = 31
anonymous
  • anonymous
and you have -x -z = 5
anonymous
  • anonymous
solve these two equations
anonymous
  • anonymous
okay
anonymous
  • anonymous
you get z = 26
anonymous
  • anonymous
x = -31
anonymous
  • anonymous
is y 30?
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
agent0smith
  • agent0smith
Assuming Kanwar245 is correct, z = 26 x = -31 to find y, use these values in one of these equations to find y: x+y=-1 y-z=4 2x+y+5z=-38 from the first, x+y=-1, so \[\large y = -1 - x = -1 - (-31) = 30 \]. or use the second, y-z=4, so \[\large y= 4+z = 4+26 = 30\] or use the third, 2x+y+5z=-38, so \[y = -38 -2x -5z = -38 -2(-31)-5(26) = -106\] This doesn't agree with the other value for y of 30, so it's possible there's a mistake somewhere.

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