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krissywatts
 2 years ago
solve system of equation:
x+y=1
yz=4
2x+y+5z=38
i need step by step help please?
krissywatts
 2 years ago
solve system of equation: x+y=1 yz=4 2x+y+5z=38 i need step by step help please?

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Kanwar245
 2 years ago
Best ResponseYou've already chosen the best response.1step1; multiply equation 1 with 1

Kanwar245
 2 years ago
Best ResponseYou've already chosen the best response.1step2; add equation 1 and equation 2

Kanwar245
 2 years ago
Best ResponseYou've already chosen the best response.1you'll get an equation in terms of x and z

krissywatts
 2 years ago
Best ResponseYou've already chosen the best response.0so my finale for that would be xz=4 correct?

krissywatts
 2 years ago
Best ResponseYou've already chosen the best response.0no what is the next step?

Kanwar245
 2 years ago
Best ResponseYou've already chosen the best response.1also you can rewrite last equation as 2x + 4 + z + 5z = 38

Kanwar245
 2 years ago
Best ResponseYou've already chosen the best response.12x + 6z = 42 or x + 2z = 31

Kanwar245
 2 years ago
Best ResponseYou've already chosen the best response.1and you have x z = 5

Kanwar245
 2 years ago
Best ResponseYou've already chosen the best response.1solve these two equations

agent0smith
 2 years ago
Best ResponseYou've already chosen the best response.0Assuming Kanwar245 is correct, z = 26 x = 31 to find y, use these values in one of these equations to find y: x+y=1 yz=4 2x+y+5z=38 from the first, x+y=1, so \[\large y = 1  x = 1  (31) = 30 \]. or use the second, yz=4, so \[\large y= 4+z = 4+26 = 30\] or use the third, 2x+y+5z=38, so \[y = 38 2x 5z = 38 2(31)5(26) = 106\] This doesn't agree with the other value for y of 30, so it's possible there's a mistake somewhere.
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