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happykiddo

  • 2 years ago

How is this factored::::: 125x^3-27=0 using the sum or difference of cubes to find the real or imaginary solutions

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  1. Mertsj
    • 2 years ago
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    difference of two cubes.

  2. Mertsj
    • 2 years ago
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    (5x)^3-(3)^3

  3. happykiddo
    • 2 years ago
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    but what about the part where you plug it into the formula my real question is does the -3 stay negativ when plug-in her into the formula where the -b is

  4. campbell_st
    • 2 years ago
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    the general form is \[a^3 - b^3 = (a -b)(a^2 + ab + b^2)\] in your question a = 5x and b = 3

  5. happykiddo
    • 2 years ago
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    thanks :) i wrote the formula wrong

  6. campbell_st
    • 2 years ago
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    glad to help

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