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happykiddo
How is this factored::::: 125x^3-27=0 using the sum or difference of cubes to find the real or imaginary solutions
difference of two cubes.
but what about the part where you plug it into the formula my real question is does the -3 stay negativ when plug-in her into the formula where the -b is
the general form is \[a^3 - b^3 = (a -b)(a^2 + ab + b^2)\] in your question a = 5x and b = 3
thanks :) i wrote the formula wrong