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solve system of equation:
x+y=1
yz=4
2x+y+5z=38
i need step by step help please?
 one year ago
 one year ago
solve system of equation: x+y=1 yz=4 2x+y+5z=38 i need step by step help please?
 one year ago
 one year ago

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campbell_stBest ResponseYou've already chosen the best response.1
ok... take the 2nd equation y  z = 4 and multiply it by 5 so you get 5y  5z = 20 now add it to the last equation this will eliminate z 5y  5z = 20 2x + y + 5z = 38  2x + 6y = 18 now you have 2 equations in 2 unknowns... which is easier to solve you can divide the equation by 2 to make easier x + 3y = 9 and x + y = 1 a little subtraction x + 3y = 9 x  y = 1  2y = 8 so y = 4 substitute the value of y into the 1st equation to find x x  4 = 1 when you have x substitute your value of y into the 2nd equation to find z 4  z = 4 hope this helps
 one year ago

krissywattsBest ResponseYou've already chosen the best response.0
and z is equal t0 7 corretc?
 one year ago

krissywattsBest ResponseYou've already chosen the best response.0
and x is 3 correct?
 one year ago

campbell_stBest ResponseYou've already chosen the best response.1
yep... I think thats it
 one year ago

krissywattsBest ResponseYou've already chosen the best response.0
thank yo so much. You work fast :)
 one year ago
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