anonymous
  • anonymous
solve system of equation: x+y=-1 y-z=4 2x+y+5z=-38 i need step by step help please?
Mathematics
chestercat
  • chestercat
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campbell_st
  • campbell_st
ok... take the 2nd equation y - z = 4 and multiply it by 5 so you get 5y - 5z = 20 now add it to the last equation this will eliminate z 5y - 5z = 20 2x + y + 5z = -38 ------------------ 2x + 6y = -18 now you have 2 equations in 2 unknowns... which is easier to solve you can divide the equation by 2 to make easier x + 3y = -9 and x + y = -1 a little subtraction x + 3y = -9 -x - y = 1 ------------- 2y = -8 so y = -4 substitute the value of y into the 1st equation to find x x - 4 = -1 when you have x substitute your value of y into the 2nd equation to find z -4 - z = 4 hope this helps
anonymous
  • anonymous
okay thanks
anonymous
  • anonymous
and z is equal t0 7 corretc?

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anonymous
  • anonymous
@campbell_st
campbell_st
  • campbell_st
no I think z = -8
anonymous
  • anonymous
and x is 3 correct?
campbell_st
  • campbell_st
yep... I think thats it
anonymous
  • anonymous
thank yo so much. You work fast :)

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