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anonymous
 3 years ago
solve system of equation:
x+y=1
yz=4
2x+y+5z=38
i need step by step help please?
anonymous
 3 years ago
solve system of equation: x+y=1 yz=4 2x+y+5z=38 i need step by step help please?

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campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.1ok... take the 2nd equation y  z = 4 and multiply it by 5 so you get 5y  5z = 20 now add it to the last equation this will eliminate z 5y  5z = 20 2x + y + 5z = 38  2x + 6y = 18 now you have 2 equations in 2 unknowns... which is easier to solve you can divide the equation by 2 to make easier x + 3y = 9 and x + y = 1 a little subtraction x + 3y = 9 x  y = 1  2y = 8 so y = 4 substitute the value of y into the 1st equation to find x x  4 = 1 when you have x substitute your value of y into the 2nd equation to find z 4  z = 4 hope this helps

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and z is equal t0 7 corretc?

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.1yep... I think thats it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank yo so much. You work fast :)
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