## chubbytots 2 years ago 5x^2-32x+12=

1. andreafortune1

2. chubbytots

\[5x^2-32x+12=\]

3. Hope_nicole

have you tried factoring it?

4. chubbytots

nope,,..

5. chubbytots

ohh i means yess

6. lasttccasey

You need this to equal something in order to solve for x or you need an x to see what it equals.

7. lasttccasey

Is this factoring?

8. chubbytots

solve for x

9. chubbytots

its like factoring diamod

10. lasttccasey

(x-6)(5x-2)=? you can't solve x without it equaling zero or something.

11. chubbytots

okey thankx :)

12. chubbytots

\[6x^2+5x-4=\]

13. lasttccasey

=(2x-1)(3x+4) Do you understand how to factor these?

14. bangabus000

5x^2-30x-2x=12 5X(X-6) -2(X-6) (5X-2) (X-6) X=2/5 and x=6

15. chubbytots

no.. u, u\

16. bangabus000

*5x^2-30x-2x+12 not equals 12 on the first row

17. lasttccasey

@bangabus000 Thats technically incorrect, you can't bring over the 12 without knowing whats on the right side.

18. bangabus000

umm yeah... no i made an error while typing its plus 12 not equal

19. lasttccasey

I'm just saying, you can't solve for x if the right side is missing. it could be 0 but it could also be 100 or anything for that matter.

20. bangabus000

ofcourse its 0 on the other side. i thought that was obvious since we were factoring.

21. bangabus000

the x values are correct right?

22. lasttccasey

@chubbytots But using bangabus000's method, factoring by parts, is the best way to solve this type. @bangabus000 If it equals zero yes :)

23. bangabus000

hehehe :p