anonymous
  • anonymous
5x^2-32x+12=
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
is -10 a answer?
anonymous
  • anonymous
\[5x^2-32x+12=\]
anonymous
  • anonymous
have you tried factoring it?

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anonymous
  • anonymous
nope,,..
anonymous
  • anonymous
ohh i means yess
lasttccasey
  • lasttccasey
You need this to equal something in order to solve for x or you need an x to see what it equals.
lasttccasey
  • lasttccasey
Is this factoring?
anonymous
  • anonymous
solve for x
anonymous
  • anonymous
its like factoring diamod
lasttccasey
  • lasttccasey
(x-6)(5x-2)=? you can't solve x without it equaling zero or something.
anonymous
  • anonymous
okey thankx :)
anonymous
  • anonymous
\[6x^2+5x-4=\]
lasttccasey
  • lasttccasey
=(2x-1)(3x+4) Do you understand how to factor these?
anonymous
  • anonymous
5x^2-30x-2x=12 5X(X-6) -2(X-6) (5X-2) (X-6) X=2/5 and x=6
anonymous
  • anonymous
no.. u, u\
anonymous
  • anonymous
*5x^2-30x-2x+12 not equals 12 on the first row
lasttccasey
  • lasttccasey
@bangabus000 Thats technically incorrect, you can't bring over the 12 without knowing whats on the right side.
anonymous
  • anonymous
umm yeah... no i made an error while typing its plus 12 not equal
lasttccasey
  • lasttccasey
I'm just saying, you can't solve for x if the right side is missing. it could be 0 but it could also be 100 or anything for that matter.
anonymous
  • anonymous
ofcourse its 0 on the other side. i thought that was obvious since we were factoring.
anonymous
  • anonymous
the x values are correct right?
lasttccasey
  • lasttccasey
@chubbytots But using bangabus000's method, factoring by parts, is the best way to solve this type. @bangabus000 If it equals zero yes :)
anonymous
  • anonymous
hehehe :p

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