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chubbytots

  • one year ago

5x^2-32x+12=

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  1. andreafortune1
    • one year ago
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    is -10 a answer?

  2. chubbytots
    • one year ago
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    \[5x^2-32x+12=\]

  3. Hope_nicole
    • one year ago
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    have you tried factoring it?

  4. chubbytots
    • one year ago
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    nope,,..

  5. chubbytots
    • one year ago
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    ohh i means yess

  6. lasttccasey
    • one year ago
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    You need this to equal something in order to solve for x or you need an x to see what it equals.

  7. lasttccasey
    • one year ago
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    Is this factoring?

  8. chubbytots
    • one year ago
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    solve for x

  9. chubbytots
    • one year ago
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    its like factoring diamod

  10. lasttccasey
    • one year ago
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    (x-6)(5x-2)=? you can't solve x without it equaling zero or something.

  11. chubbytots
    • one year ago
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    okey thankx :)

  12. chubbytots
    • one year ago
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    \[6x^2+5x-4=\]

  13. lasttccasey
    • one year ago
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    =(2x-1)(3x+4) Do you understand how to factor these?

  14. bangabus000
    • one year ago
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    5x^2-30x-2x=12 5X(X-6) -2(X-6) (5X-2) (X-6) X=2/5 and x=6

  15. chubbytots
    • one year ago
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    no.. u, u\

  16. bangabus000
    • one year ago
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    *5x^2-30x-2x+12 not equals 12 on the first row

  17. lasttccasey
    • one year ago
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    @bangabus000 Thats technically incorrect, you can't bring over the 12 without knowing whats on the right side.

  18. bangabus000
    • one year ago
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    umm yeah... no i made an error while typing its plus 12 not equal

  19. lasttccasey
    • one year ago
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    I'm just saying, you can't solve for x if the right side is missing. it could be 0 but it could also be 100 or anything for that matter.

  20. bangabus000
    • one year ago
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    ofcourse its 0 on the other side. i thought that was obvious since we were factoring.

  21. bangabus000
    • one year ago
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    the x values are correct right?

  22. lasttccasey
    • one year ago
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    @chubbytots But using bangabus000's method, factoring by parts, is the best way to solve this type. @bangabus000 If it equals zero yes :)

  23. bangabus000
    • one year ago
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    hehehe :p

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