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liliy
Group Title
The Mean Value Theorem of integrals says that if f is continuous on a closed bounded interval [a, b], there exists a number c, between a and b, such that Integral of f[x] dx =f (c) (b  a)
Find the value c that satifies the mean value theorem for f(x) = ln(x) on the interval [1,2]
 one year ago
 one year ago
liliy Group Title
The Mean Value Theorem of integrals says that if f is continuous on a closed bounded interval [a, b], there exists a number c, between a and b, such that Integral of f[x] dx =f (c) (b  a) Find the value c that satifies the mean value theorem for f(x) = ln(x) on the interval [1,2]
 one year ago
 one year ago

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amistre64 Group TitleBest ResponseYou've already chosen the best response.0
height times length .... equals area
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
integrate ln(x) from 1 to 2, and divide it by the length of the interval .... stuff like that
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
do you know how to compote \[\int_1^2\ln(x)dx\]?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
*compute
 one year ago

liliy Group TitleBest ResponseYou've already chosen the best response.0
I got the answer to be log[2] ?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
integrate ln(x), xlnx  x (2 ln2  2)  (1ln1  1) 2 ln2  1 ln4  1, and since ba = 21 = 1, we get ln(c) = ln4  1 c = e^(ln4  1) c = 4  e^(1) right?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
err, 4e^(1) might be better
 one year ago

liliy Group TitleBest ResponseYou've already chosen the best response.0
I dont undestnad what i am integrating... you are you also doing xlnxx?
 one year ago
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