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The Mean Value Theorem of integrals says that if f is continuous on a closed bounded interval [a, b], there exists a number c, between a and b, such that Integral of f[x] dx =f (c) (b  a)
Find the value c that satifies the mean value theorem for f(x) = ln(x) on the interval [1,2]
 one year ago
 one year ago
The Mean Value Theorem of integrals says that if f is continuous on a closed bounded interval [a, b], there exists a number c, between a and b, such that Integral of f[x] dx =f (c) (b  a) Find the value c that satifies the mean value theorem for f(x) = ln(x) on the interval [1,2]
 one year ago
 one year ago

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amistre64Best ResponseYou've already chosen the best response.0
height times length .... equals area
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
integrate ln(x) from 1 to 2, and divide it by the length of the interval .... stuff like that
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
do you know how to compote \[\int_1^2\ln(x)dx\]?
 one year ago

liliyBest ResponseYou've already chosen the best response.0
I got the answer to be log[2] ?
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
integrate ln(x), xlnx  x (2 ln2  2)  (1ln1  1) 2 ln2  1 ln4  1, and since ba = 21 = 1, we get ln(c) = ln4  1 c = e^(ln4  1) c = 4  e^(1) right?
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
err, 4e^(1) might be better
 one year ago

liliyBest ResponseYou've already chosen the best response.0
I dont undestnad what i am integrating... you are you also doing xlnxx?
 one year ago
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