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Jonask Group TitleBest ResponseYou've already chosen the best response.1
\[\sin^3x=\sin x \sin^2x\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
i think the gimmick is to rewrite this as \[\sin^2(x)\sin(x)=(1\cos^2(x))\sin(x)\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
then \[\sin(x)\sin(x)\cos^2(x)\] first integral is easy, second is a u  sub
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
or you can look at the "reduction" formula for sine on the inside cover of the back off your text and use \(n=3\)
 one year ago

Trustted Group TitleBest ResponseYou've already chosen the best response.0
HMMMM.. Tnx guys.. can u give me a site for online lessons
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[\sin^3x=\sin x \sin^2x\\\qquad=\sin x\frac{1\cos(2x)}2\\\qquad=\tfrac12\big(\sin x\sin x\cos(2x)\big)\\\qquad=\tfrac12\Big(\sin x\frac{\sin(3x)+\sin(x)}{2}\Big)\\\qquad=\frac {\sin x}2\frac{\sin(3x)}{4}+\frac{\sin(x)}{4}\]
 one year ago
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