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Carniel

  • 2 years ago

A beam of electrons moves at right angles to a magnetic field of 4.5 × 10^-2 tesla. If the electrons have a velocity of 6.5 × 106 meters/second, what is the force acting on the electrons? The value of q = -1.6 × 10^-19 coulombs.Select one of the options below as your answer: A. -2.9 × 106 N B. -4.9 × 10^-14 N C. -4.9 × 10^-14 N D. -6.5 × 10^-13 N

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  1. Carniel
    • 2 years ago
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    Plz help :'(

  2. kausarsalley
    • 2 years ago
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    F = Bqv sin theta F=Force B=magnetic flux density q=charge v=velocity theta=angle the moving electrons make with the magnetic field.

  3. kausarsalley
    • 2 years ago
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    do you understand it now??

  4. Carniel
    • 2 years ago
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    Not really :(

  5. Carniel
    • 2 years ago
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    Can u plz explain what I'm suppose to do to find the answer in a clear mannor. Really trying to specialize in Physics.

  6. kausarsalley
    • 2 years ago
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    you are finding the force so using that formula, |dw:1363635861462:dw|

  7. kausarsalley
    • 2 years ago
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    does that help??

  8. kausarsalley
    • 2 years ago
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    i think you made a mistake in writing the possible answer.....B and C have the same value

  9. Carniel
    • 2 years ago
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    Thx and this is what the teacher gave us.

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