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A beam of electrons moves at right angles to a magnetic field of 4.5 × 10^2 tesla. If the electrons have a velocity of 6.5 × 106 meters/second, what is the force acting on the electrons? The value of q = 1.6 × 10^19 coulombs.Select one of the options below as your answer: A. 2.9 × 106 N B. 4.9 × 10^14 N C. 4.9 × 10^14 N D. 6.5 × 10^13 N
 one year ago
 one year ago
A beam of electrons moves at right angles to a magnetic field of 4.5 × 10^2 tesla. If the electrons have a velocity of 6.5 × 106 meters/second, what is the force acting on the electrons? The value of q = 1.6 × 10^19 coulombs.Select one of the options below as your answer: A. 2.9 × 106 N B. 4.9 × 10^14 N C. 4.9 × 10^14 N D. 6.5 × 10^13 N
 one year ago
 one year ago

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kausarsalleyBest ResponseYou've already chosen the best response.1
F = Bqv sin theta F=Force B=magnetic flux density q=charge v=velocity theta=angle the moving electrons make with the magnetic field.
 one year ago

kausarsalleyBest ResponseYou've already chosen the best response.1
do you understand it now??
 one year ago

CarnielBest ResponseYou've already chosen the best response.0
Can u plz explain what I'm suppose to do to find the answer in a clear mannor. Really trying to specialize in Physics.
 one year ago

kausarsalleyBest ResponseYou've already chosen the best response.1
you are finding the force so using that formula, dw:1363635861462:dw
 one year ago

kausarsalleyBest ResponseYou've already chosen the best response.1
i think you made a mistake in writing the possible answer.....B and C have the same value
 one year ago

CarnielBest ResponseYou've already chosen the best response.0
Thx and this is what the teacher gave us.
 one year ago
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