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yashar806
Need help, see attachments
(a) The mean is \[205\times 0.15=?\] The standard deviation is \[\sqrt{(205\times 0.15\times 0.85)}\]
i got 5.1125 something
I need help with last one
can you help on last one , cuz I really don't get t
(c) This part can be solved by using the Normal Approximation of the Binomial Distribution. As found in part (a) the mean = 31 and the standard deviation = 5.112. There are 27 seats available for left handed people so we need to find the probability that the number of left handed people is equal to, or fewer than 27. In this case the z-score is calculated as follows: \[z=\frac{27-31+0.5}{5.112}=-0.6847\] Note: The term 0.5 in this calculation is a correction caused by the change from a discrete to a continuous distribution. A standard normal probability table gives a cumulative probability of 0.247
i need to use that for last one
p hat is equal to = x/n
The question you have posted does not involve sampling. Therefore the formula you have posted does not apply.