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yashar806 Group TitleBest ResponseYou've already chosen the best response.0
is it potssible?
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.1
(a) The mean is \[205\times 0.15=?\] The standard deviation is \[\sqrt{(205\times 0.15\times 0.85)}\]
 one year ago

yashar806 Group TitleBest ResponseYou've already chosen the best response.0
i got 5.1125 something
 one year ago

yashar806 Group TitleBest ResponseYou've already chosen the best response.0
I need help with last one
 one year ago

yashar806 Group TitleBest ResponseYou've already chosen the best response.0
can you help on last one , cuz I really don't get t
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.1
(c) This part can be solved by using the Normal Approximation of the Binomial Distribution. As found in part (a) the mean = 31 and the standard deviation = 5.112. There are 27 seats available for left handed people so we need to find the probability that the number of left handed people is equal to, or fewer than 27. In this case the zscore is calculated as follows: \[z=\frac{2731+0.5}{5.112}=0.6847\] Note: The term 0.5 in this calculation is a correction caused by the change from a discrete to a continuous distribution. A standard normal probability table gives a cumulative probability of 0.247
 one year ago

yashar806 Group TitleBest ResponseYou've already chosen the best response.0
i have that formula
 one year ago

yashar806 Group TitleBest ResponseYou've already chosen the best response.0
i need to use that for last one
 one year ago

yashar806 Group TitleBest ResponseYou've already chosen the best response.0
p hat is equal to = x/n
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.1
The question you have posted does not involve sampling. Therefore the formula you have posted does not apply.
 one year ago
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