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yashar806

  • one year ago

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  1. yashar806
    • one year ago
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  2. zakrocks007
    • one year ago
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    10

  3. zakrocks007
    • one year ago
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    10

  4. yashar806
    • one year ago
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    is it potssible?

  5. kropot72
    • one year ago
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    (a) The mean is \[205\times 0.15=?\] The standard deviation is \[\sqrt{(205\times 0.15\times 0.85)}\]

  6. yashar806
    • one year ago
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    i got 5.1125 something

  7. yashar806
    • one year ago
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    I need help with last one

  8. yashar806
    • one year ago
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    can you help on last one , cuz I really don't get t

  9. kropot72
    • one year ago
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    (c) This part can be solved by using the Normal Approximation of the Binomial Distribution. As found in part (a) the mean = 31 and the standard deviation = 5.112. There are 27 seats available for left handed people so we need to find the probability that the number of left handed people is equal to, or fewer than 27. In this case the z-score is calculated as follows: \[z=\frac{27-31+0.5}{5.112}=-0.6847\] Note: The term 0.5 in this calculation is a correction caused by the change from a discrete to a continuous distribution. A standard normal probability table gives a cumulative probability of 0.247

  10. yashar806
    • one year ago
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  11. yashar806
    • one year ago
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    i have that formula

  12. yashar806
    • one year ago
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    i need to use that for last one

  13. yashar806
    • one year ago
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    p hat is equal to = x/n

  14. kropot72
    • one year ago
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    The question you have posted does not involve sampling. Therefore the formula you have posted does not apply.

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