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zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Hmm so it looks like this is separable. Just takes a little bit of work on the right side. Factor by grouping. \[\large y'=1xyy+x\]Factoring a y out of each of the middle terms gives us,\[\large y'=1y(x+1)+x\]We'll rewrite it like this,\[\large y'=(x+1)y(x+1)\]Now we can factor an x+1 out of each term, giving us,\[\large y'=(x+1)(1y)\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Separating variables gives us,\[\large \frac{dy}{1y}=(x+1)dx\] Understand how to solve it from here? :o

soumyan
 one year ago
Best ResponseYou've already chosen the best response.0thanks for solution..... i done this method in my exam and today or by tomorrow i wil get my result... i wanted to confirm.... thank u so much...

mathslover
 one year ago
Best ResponseYou've already chosen the best response.0And also @soumyan : \[\large{\color{orange}{\textbf{WELCOME TO OPENSTUDY}}}\]
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