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anonymous
 3 years ago
A super MATH riddle!
You can place weights on both side of weighing balance and you need to measure all weights between 1 and 1000. For example if you have weights 1 and 3,now you can measure 1,3 and 4 like earlier case, and also you can measure 2,by placing 3 on one side and 1 on the side which contain the substance to be weighed. So question again is how many minimum weights and of what denominations you need to measure all weights from 1kg to 1000kg.
anonymous
 3 years ago
A super MATH riddle! You can place weights on both side of weighing balance and you need to measure all weights between 1 and 1000. For example if you have weights 1 and 3,now you can measure 1,3 and 4 like earlier case, and also you can measure 2,by placing 3 on one side and 1 on the side which contain the substance to be weighed. So question again is how many minimum weights and of what denominations you need to measure all weights from 1kg to 1000kg.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Here is the first, @theawesome

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I give up. Cant do it!

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.0Each weight has three possible states: 1) On the left 2) On the right 3) Off the scale Please consider powers of 3 as a complete solution.

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.01, 3, 9, 27, 81, 243, 729 , GP... ? right?

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.0729+243+81 > 1000  I think you have it.
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