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A super MATH riddle!
You can place weights on both side of weighing balance and you need to measure all weights between 1 and 1000. For example if you have weights 1 and 3,now you can measure 1,3 and 4 like earlier case, and also you can measure 2,by placing 3 on one side and 1 on the side which contain the substance to be weighed. So question again is how many minimum weights and of what denominations you need to measure all weights from 1kg to 1000kg.
 one year ago
 one year ago
A super MATH riddle! You can place weights on both side of weighing balance and you need to measure all weights between 1 and 1000. For example if you have weights 1 and 3,now you can measure 1,3 and 4 like earlier case, and also you can measure 2,by placing 3 on one side and 1 on the side which contain the substance to be weighed. So question again is how many minimum weights and of what denominations you need to measure all weights from 1kg to 1000kg.
 one year ago
 one year ago

This Question is Open

Dr.ProfessorBest ResponseYou've already chosen the best response.1
Here is the first, @theawesome
 one year ago

Dr.ProfessorBest ResponseYou've already chosen the best response.1
Sir, please try it!
 one year ago

NumbersCantLIEBest ResponseYou've already chosen the best response.0
I give up. Cant do it!
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
Each weight has three possible states: 1) On the left 2) On the right 3) Off the scale Please consider powers of 3 as a complete solution.
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
1, 3, 9, 27, 81, 243, 729 , GP... ? right?
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
729+243+81 > 1000  I think you have it.
 one year ago
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