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statistics....we meet again.

LOL. Are you not so good with them?

not so good is an overstatement.

*understatement. I suck at it.

Oh, ok. thats fine, no worries. Ill go beg someone else.
:D

Thanks for looking,tho.

http://www.purplemath.com/modules/boxwhisk3.htm

see if this helps :)

Hmm... could you explain it step by step?

hold on

ok. ty:)

you find the median of your data.

have u done that

one second - let me do it.

Median: 68

hmmm.

let me read all that.

srry

why are you sorry?

too much to read :)

indeed. lol.

could u simplify it?

divide the data into quarters, you then find the medians of these two halves.

hmmm...could u show me the steps by using the DRAW button?

Please.

im not surehttp://www.purplemath.com/modules/boxwhisk.htm

Hmm. Okay. Thanks.

Lets see.....

what's your question?

I also would like to know how to make box and whisker plots by myself.

the median is 68.

ok.....hmmm...

oohhhh divide it into 2?

8/2=4

so 4 sets of data in the lower quartile and 4 in the upper?

yes the median is 68

Okay.

show me step by step how to make it using the DRAW button please?

Uh-huh, I see.

the median of 61, 64, 65, 68 is 64.5, so Q1 = 64.5

Okay.

what's Q3?

Let me see. One second.

70.5

good

what's your IQR

i don't know how to get that...

IQR = Q3 - Q1

it's basically the distance from each endpoint of the box

Oh,ok.

70.5-64.5?

yep

thats 6.

now find the min and max

The min and max?

yes, the smallest and largest data values

oh... U mean
min = 61
max = 73

good, now determine if the min is an outlier or not

you do this by seeing if the min is above
median - 1.5*IQR

Why 1.5?

I think it was Tukey

Oh.

I'm not sure how or why he got 1.5, but it works

and people agree on it

and the iqr is?

you just found it

o sorry....6

yep

1.5 x 6 = 9

subtract that from the median 68

Hmm. Ok. WOW, lots of steps
:/
LOL.

it's not so bad once you get used to them

56.

68 - 9 is not 56

it's 59

o right sorry.

so that's your lowest threshold

i punched the wrong numbers into the calculator.

basically that's the smallest the min can be

sorry bout that.

any smaller than 59, and the min is an outlier

Ah,ok.

now compute
median + 1.5*IQR

Mhmm. Okay. One second - will log off for like 2 mins,k?

ill brb

im back

did you find
median + 1.5*IQR

lets see. the median was?

68. so 68-9...
59?

you already did that one

its not the answer?

no I wanted you to find
median + 1.5*IQR

Oh...Ok.

68+1.5*9

yeah but the IQR is 6, not 9

right,sorry

77

good, is the max smaller or larger than 77?

The max is 73, so its larger.

you mean, the max is smaller than 77?

Right.

so does that make the max an outlier?

no.

wait..

so there are no outliers

you're correct

nvm.

oh,okay.

so you have enough info to plot the box and whisker plot

Alright,thanks!

Yes.

|dw:1363736267701:dw|

this is if you don't have any outliers

Okay. I think I understand a bit better- thanks!