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help123please.
 2 years ago
Display the data in the chart attached below by making a box and whisker plot.
Explain how you made it.
help123please.
 2 years ago
Display the data in the chart attached below by making a box and whisker plot. Explain how you made it.

This Question is Closed

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.0statistics....we meet again.

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0LOL. Are you not so good with them?

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.0not so good is an overstatement.

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.0*understatement. I suck at it.

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0Oh, ok. thats fine, no worries. Ill go beg someone else. :D

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0Thanks for looking,tho.

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0Hmm... could you explain it step by step?

pooja195
 2 years ago
Best ResponseYou've already chosen the best response.0you find the median of your data.

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0one second  let me do it.

pooja195
 2 years ago
Best ResponseYou've already chosen the best response.0goodTo divide the data into quarters, you then find the medians of these two halves. Note: If you have an even number of values, so the first median was the average of the two middle values, then you include the middle values in your submedian computations. If you have an odd number of values, so the first median was an actual data point, then you do not include that value in your submedian computations. That is, to find the submedians, you're only looking at the values that haven't yet been used

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0let me read all that.

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0why are you sorry?

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0could u simplify it?

pooja195
 2 years ago
Best ResponseYou've already chosen the best response.0divide the data into quarters, you then find the medians of these two halves.

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0hmmm...could u show me the steps by using the DRAW button?

pooja195
 2 years ago
Best ResponseYou've already chosen the best response.0im not sure http://www.purplemath.com/modules/boxwhisk.htm

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0Hmm. Okay. Thanks.

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2what's your question?

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0I have to make a box and whisker plot for the data shown at http://assets.openstudy.com/updates/attachments/5148e6dee4b05e69bfab6578help123please.1363732200597screenshot20130319at5.28.53pm.png

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0I also would like to know how to make box and whisker plots by myself.

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2Find the median first Then split the data into two groups (the median is the cut off point) and find the median of each group. The first quartile is the median of the lower half, the third quartile is the median of the upper half

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0the median is 68.

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0oohhhh divide it into 2?

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0so 4 sets of data in the lower quartile and 4 in the upper?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2yes the median is 68

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0show me step by step how to make it using the DRAW button please?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2so the sorted number set 61, 64, 65, 68, 68, 70, 71, 73 turns into 61, 64, 65, 68  68, 70, 71, 73 when you split the data in half along the median

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2the median of 61, 64, 65, 68 is 64.5, so Q1 = 64.5

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0Let me see. One second.

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2what's your IQR

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0i don't know how to get that...

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2it's basically the distance from each endpoint of the box

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2now find the min and max

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0The min and max?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2yes, the smallest and largest data values

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0oh... U mean min = 61 max = 73

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2good, now determine if the min is an outlier or not

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2you do this by seeing if the min is above median  1.5*IQR

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2just a number that some statistician a long time ago determined was the best number to see if outliers exist on a box and whisker plot

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2I think it was Tukey

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2I'm not sure how or why he got 1.5, but it works

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2and people agree on it

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2you just found it

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2subtract that from the median 68

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0Hmm. Ok. WOW, lots of steps :/ LOL.

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2it's not so bad once you get used to them

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.268  9 is not 56

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2so that's your lowest threshold

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0i punched the wrong numbers into the calculator.

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2basically that's the smallest the min can be

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0sorry bout that.

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2any smaller than 59, and the min is an outlier

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2so we do NOT have an outlier for the min because the min (which is 61) is greater than the threshold of 59

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2now compute median + 1.5*IQR

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0Mhmm. Okay. One second  will log off for like 2 mins,k?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2did you find median + 1.5*IQR

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0lets see. the median was?

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.068. so 689... 59?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2you already did that one

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0its not the answer?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2no I wanted you to find median + 1.5*IQR

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2yeah but the IQR is 6, not 9

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2good, is the max smaller or larger than 77?

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0The max is 73, so its larger.

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2you mean, the max is smaller than 77?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2so does that make the max an outlier?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2so there are no outliers

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2you're correct

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2so you have enough info to plot the box and whisker plot

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2The basic format (the chances of your box and whisker plot looking exactly like this are very slim) is this dw:1363736245038:dw

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2dw:1363736267701:dw

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2this is if you don't have any outliers

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0Okay. I think I understand a bit better thanks!
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