The graph below represents which system of inequalities? A) y < -2x + 6 y < x + 2 B) y <= -2x + 6 y <= x + 2 C) y < 2/3x - 2 y > 2x + 2 D) None of the above

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The graph below represents which system of inequalities? A) y < -2x + 6 y < x + 2 B) y <= -2x + 6 y <= x + 2 C) y < 2/3x - 2 y > 2x + 2 D) None of the above

Mathematics
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which choice can we automatically eliminating

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eliminate*
I don't know. that is the problem.
we can automatically eliminate b because the lines in the graph are dashed, not solid. and <= would be a solid line
now you can graph a and c and see which choice is the answer
So it is either A or C?
or d
I think it is D.
have you tried graphing though
on paper, yeah. I think that is it.
i just graphed a and this is what it looks like. a is your answer
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Okay thank you!
how did you graph it
not like that. can you show me how you did that?
y < -2x + 6 start by plotting the y-intercept which in this case is 6. so make a point at (0,6) then use the slope which is -2. slope is rise/run, so from (0,6), go down 2 and over to the right 1
then make a point there and make a dashed line
ohhhhh okay! is that all?
and you would shade under the line
yea, then just do it to the other line and you should get it
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Okay, so now for this one: The graph below represents which system of inequalities? y <= -2x + 3 y <= x + 3 y >= -2x + 3 y >= x + 3 y <= -3x + 2 y <= -x + 2 y > -2x + 3 y > x + 3
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oh. do you think you can try that one yourself?
I did. none of my graphs matched that one.
can i see your graphs
yes, but can you tell me how to do the x axis part? Imma go over my graphs and check.
what do you mean?
how do i plot and stuff on my graph for the x axis. i think i did it wrong.
you plot the y-intercept first. then use the slope to plot the next point
which is?
here i'll use this as an example y <= -2x + 3 the y-intercept is 3. so the first point you need to plot is (0,3). the slope is -2. slope is rise/run. so from the point (0,3), go down 2 and over to the right 1, which would be (1,1). plot a point there. since the inequality is <=, our line is solid. so make a solid line through your two points. shade under the line.
|dw:1363736756403:dw|
something like this?
yes
now plot this one on the same graph y <= x + 3
like add that to the graph i just made?
yes
|dw:1363737069536:dw|
why did you make a point there |dw:1363737269524:dw|
oh. i wasnt sure so i kinda guessed..

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