anonymous
  • anonymous
The graph below represents which system of inequalities? A) y < -2x + 6 y < x + 2 B) y <= -2x + 6 y <= x + 2 C) y < 2/3x - 2 y > 2x + 2 D) None of the above
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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anonymous
  • anonymous
@Mertsj
AriPotta
  • AriPotta
which choice can we automatically eliminating

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AriPotta
  • AriPotta
eliminate*
anonymous
  • anonymous
I don't know. that is the problem.
AriPotta
  • AriPotta
we can automatically eliminate b because the lines in the graph are dashed, not solid. and <= would be a solid line
AriPotta
  • AriPotta
now you can graph a and c and see which choice is the answer
anonymous
  • anonymous
So it is either A or C?
AriPotta
  • AriPotta
or d
anonymous
  • anonymous
I think it is D.
AriPotta
  • AriPotta
have you tried graphing though
anonymous
  • anonymous
on paper, yeah. I think that is it.
anonymous
  • anonymous
@SingleSixxs_Fiance
AriPotta
  • AriPotta
i just graphed a and this is what it looks like. a is your answer
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anonymous
  • anonymous
Okay thank you!
AriPotta
  • AriPotta
how did you graph it
anonymous
  • anonymous
not like that. can you show me how you did that?
AriPotta
  • AriPotta
y < -2x + 6 start by plotting the y-intercept which in this case is 6. so make a point at (0,6) then use the slope which is -2. slope is rise/run, so from (0,6), go down 2 and over to the right 1
AriPotta
  • AriPotta
then make a point there and make a dashed line
anonymous
  • anonymous
ohhhhh okay! is that all?
AriPotta
  • AriPotta
and you would shade under the line
AriPotta
  • AriPotta
yea, then just do it to the other line and you should get it
AriPotta
  • AriPotta
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anonymous
  • anonymous
Okay, so now for this one: The graph below represents which system of inequalities? y <= -2x + 3 y <= x + 3 y >= -2x + 3 y >= x + 3 y <= -3x + 2 y <= -x + 2 y > -2x + 3 y > x + 3
AriPotta
  • AriPotta
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anonymous
  • anonymous
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AriPotta
  • AriPotta
oh. do you think you can try that one yourself?
anonymous
  • anonymous
I did. none of my graphs matched that one.
AriPotta
  • AriPotta
can i see your graphs
anonymous
  • anonymous
yes, but can you tell me how to do the x axis part? Imma go over my graphs and check.
AriPotta
  • AriPotta
what do you mean?
anonymous
  • anonymous
how do i plot and stuff on my graph for the x axis. i think i did it wrong.
AriPotta
  • AriPotta
you plot the y-intercept first. then use the slope to plot the next point
anonymous
  • anonymous
which is?
AriPotta
  • AriPotta
here i'll use this as an example y <= -2x + 3 the y-intercept is 3. so the first point you need to plot is (0,3). the slope is -2. slope is rise/run. so from the point (0,3), go down 2 and over to the right 1, which would be (1,1). plot a point there. since the inequality is <=, our line is solid. so make a solid line through your two points. shade under the line.
anonymous
  • anonymous
|dw:1363736756403:dw|
anonymous
  • anonymous
something like this?
AriPotta
  • AriPotta
yes
AriPotta
  • AriPotta
now plot this one on the same graph y <= x + 3
anonymous
  • anonymous
like add that to the graph i just made?
AriPotta
  • AriPotta
yes
anonymous
  • anonymous
|dw:1363737069536:dw|
AriPotta
  • AriPotta
why did you make a point there |dw:1363737269524:dw|
anonymous
  • anonymous
oh. i wasnt sure so i kinda guessed..
anonymous
  • anonymous
@dmezzullo

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