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Haleyy_Bugg

  • one year ago

The graph below represents which system of inequalities? A) y < -2x + 6 y < x + 2 B) y <= -2x + 6 y <= x + 2 C) y < 2/3x - 2 y > 2x + 2 D) None of the above

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  1. Haleyy_Bugg
    • one year ago
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  2. Haleyy_Bugg
    • one year ago
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    @Mertsj

  3. AriPotta
    • one year ago
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    which choice can we automatically eliminating

  4. AriPotta
    • one year ago
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    eliminate*

  5. Haleyy_Bugg
    • one year ago
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    I don't know. that is the problem.

  6. AriPotta
    • one year ago
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    we can automatically eliminate b because the lines in the graph are dashed, not solid. and <= would be a solid line

  7. AriPotta
    • one year ago
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    now you can graph a and c and see which choice is the answer

  8. Haleyy_Bugg
    • one year ago
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    So it is either A or C?

  9. AriPotta
    • one year ago
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    or d

  10. Haleyy_Bugg
    • one year ago
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    I think it is D.

  11. AriPotta
    • one year ago
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    have you tried graphing though

  12. Haleyy_Bugg
    • one year ago
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    on paper, yeah. I think that is it.

  13. Haleyy_Bugg
    • one year ago
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    @SingleSixxs_Fiance

  14. AriPotta
    • one year ago
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    i just graphed a and this is what it looks like. a is your answer

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  15. Haleyy_Bugg
    • one year ago
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    Okay thank you!

  16. AriPotta
    • one year ago
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    how did you graph it

  17. Haleyy_Bugg
    • one year ago
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    not like that. can you show me how you did that?

  18. AriPotta
    • one year ago
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    y < -2x + 6 start by plotting the y-intercept which in this case is 6. so make a point at (0,6) then use the slope which is -2. slope is rise/run, so from (0,6), go down 2 and over to the right 1

  19. AriPotta
    • one year ago
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    then make a point there and make a dashed line

  20. Haleyy_Bugg
    • one year ago
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    ohhhhh okay! is that all?

  21. AriPotta
    • one year ago
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    and you would shade under the line

  22. AriPotta
    • one year ago
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    yea, then just do it to the other line and you should get it

  23. AriPotta
    • one year ago
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  24. Haleyy_Bugg
    • one year ago
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    Okay, so now for this one: The graph below represents which system of inequalities? y <= -2x + 3 y <= x + 3 y >= -2x + 3 y >= x + 3 y <= -3x + 2 y <= -x + 2 y > -2x + 3 y > x + 3

  25. AriPotta
    • one year ago
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  26. Haleyy_Bugg
    • one year ago
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  27. AriPotta
    • one year ago
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    oh. do you think you can try that one yourself?

  28. Haleyy_Bugg
    • one year ago
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    I did. none of my graphs matched that one.

  29. AriPotta
    • one year ago
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    can i see your graphs

  30. Haleyy_Bugg
    • one year ago
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    yes, but can you tell me how to do the x axis part? Imma go over my graphs and check.

  31. AriPotta
    • one year ago
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    what do you mean?

  32. Haleyy_Bugg
    • one year ago
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    how do i plot and stuff on my graph for the x axis. i think i did it wrong.

  33. AriPotta
    • one year ago
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    you plot the y-intercept first. then use the slope to plot the next point

  34. Haleyy_Bugg
    • one year ago
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    which is?

  35. AriPotta
    • one year ago
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    here i'll use this as an example y <= -2x + 3 the y-intercept is 3. so the first point you need to plot is (0,3). the slope is -2. slope is rise/run. so from the point (0,3), go down 2 and over to the right 1, which would be (1,1). plot a point there. since the inequality is <=, our line is solid. so make a solid line through your two points. shade under the line.

  36. Haleyy_Bugg
    • one year ago
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    |dw:1363736756403:dw|

  37. Haleyy_Bugg
    • one year ago
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    something like this?

  38. AriPotta
    • one year ago
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    yes

  39. AriPotta
    • one year ago
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    now plot this one on the same graph y <= x + 3

  40. Haleyy_Bugg
    • one year ago
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    like add that to the graph i just made?

  41. AriPotta
    • one year ago
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    yes

  42. Haleyy_Bugg
    • one year ago
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    |dw:1363737069536:dw|

  43. AriPotta
    • one year ago
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    why did you make a point there |dw:1363737269524:dw|

  44. Haleyy_Bugg
    • one year ago
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    oh. i wasnt sure so i kinda guessed..

  45. Haleyy_Bugg
    • one year ago
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    @dmezzullo

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