Haleyy_Bugg
The graph below represents which system of inequalities?
A) y < -2x + 6
y < x + 2
B) y <= -2x + 6
y <= x + 2
C) y < 2/3x - 2
y > 2x + 2
D) None of the above
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Haleyy_Bugg
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Haleyy_Bugg
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@Mertsj
AriPotta
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which choice can we automatically eliminating
AriPotta
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eliminate*
Haleyy_Bugg
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I don't know. that is the problem.
AriPotta
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we can automatically eliminate b because the lines in the graph are dashed, not solid. and <= would be a solid line
AriPotta
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now you can graph a and c and see which choice is the answer
Haleyy_Bugg
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So it is either A or C?
AriPotta
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or d
Haleyy_Bugg
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I think it is D.
AriPotta
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have you tried graphing though
Haleyy_Bugg
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on paper, yeah. I think that is it.
Haleyy_Bugg
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@SingleSixxs_Fiance
AriPotta
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i just graphed a and this is what it looks like. a is your answer
Haleyy_Bugg
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Okay thank you!
AriPotta
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how did you graph it
Haleyy_Bugg
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not like that. can you show me how you did that?
AriPotta
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y < -2x + 6
start by plotting the y-intercept which in this case is 6. so make a point at (0,6)
then use the slope which is -2. slope is rise/run, so from (0,6), go down 2 and over to the right 1
AriPotta
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then make a point there and make a dashed line
Haleyy_Bugg
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ohhhhh okay! is that all?
AriPotta
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and you would shade under the line
AriPotta
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yea, then just do it to the other line and you should get it
AriPotta
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Haleyy_Bugg
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Okay, so now for this one:
The graph below represents which system of inequalities?
y <= -2x + 3
y <= x + 3
y >= -2x + 3
y >= x + 3
y <= -3x + 2
y <= -x + 2
y > -2x + 3
y > x + 3
AriPotta
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Haleyy_Bugg
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AriPotta
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oh. do you think you can try that one yourself?
Haleyy_Bugg
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I did. none of my graphs matched that one.
AriPotta
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can i see your graphs
Haleyy_Bugg
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yes, but can you tell me how to do the x axis part? Imma go over my graphs and check.
AriPotta
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what do you mean?
Haleyy_Bugg
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how do i plot and stuff on my graph for the x axis. i think i did it wrong.
AriPotta
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you plot the y-intercept first. then use the slope to plot the next point
Haleyy_Bugg
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which is?
AriPotta
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here i'll use this as an example
y <= -2x + 3
the y-intercept is 3. so the first point you need to plot is (0,3).
the slope is -2. slope is rise/run. so from the point (0,3), go down 2 and over to the right 1, which would be (1,1). plot a point there.
since the inequality is <=, our line is solid. so make a solid line through your two points. shade under the line.
Haleyy_Bugg
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|dw:1363736756403:dw|
Haleyy_Bugg
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something like this?
AriPotta
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yes
AriPotta
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now plot this one on the same graph
y <= x + 3
Haleyy_Bugg
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like add that to the graph i just made?
AriPotta
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yes
Haleyy_Bugg
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|dw:1363737069536:dw|
AriPotta
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why did you make a point there
|dw:1363737269524:dw|
Haleyy_Bugg
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oh. i wasnt sure so i kinda guessed..
Haleyy_Bugg
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@dmezzullo