The graph below represents which system of inequalities?
A) y < -2x + 6
y < x + 2
B) y <= -2x + 6
y <= x + 2
C) y < 2/3x - 2
y > 2x + 2
D) None of the above

- anonymous

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- anonymous

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- anonymous

@Mertsj

- AriPotta

which choice can we automatically eliminating

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## More answers

- AriPotta

eliminate*

- anonymous

I don't know. that is the problem.

- AriPotta

we can automatically eliminate b because the lines in the graph are dashed, not solid. and <= would be a solid line

- AriPotta

now you can graph a and c and see which choice is the answer

- anonymous

So it is either A or C?

- AriPotta

or d

- anonymous

I think it is D.

- AriPotta

have you tried graphing though

- anonymous

on paper, yeah. I think that is it.

- anonymous

@SingleSixxs_Fiance

- AriPotta

i just graphed a and this is what it looks like. a is your answer

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- anonymous

Okay thank you!

- AriPotta

how did you graph it

- anonymous

not like that. can you show me how you did that?

- AriPotta

y < -2x + 6
start by plotting the y-intercept which in this case is 6. so make a point at (0,6)
then use the slope which is -2. slope is rise/run, so from (0,6), go down 2 and over to the right 1

- AriPotta

then make a point there and make a dashed line

- anonymous

ohhhhh okay! is that all?

- AriPotta

and you would shade under the line

- AriPotta

yea, then just do it to the other line and you should get it

- AriPotta

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- anonymous

Okay, so now for this one:
The graph below represents which system of inequalities?
y <= -2x + 3
y <= x + 3
y >= -2x + 3
y >= x + 3
y <= -3x + 2
y <= -x + 2
y > -2x + 3
y > x + 3

- AriPotta

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- anonymous

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- AriPotta

oh. do you think you can try that one yourself?

- anonymous

I did. none of my graphs matched that one.

- AriPotta

can i see your graphs

- anonymous

yes, but can you tell me how to do the x axis part? Imma go over my graphs and check.

- AriPotta

what do you mean?

- anonymous

how do i plot and stuff on my graph for the x axis. i think i did it wrong.

- AriPotta

you plot the y-intercept first. then use the slope to plot the next point

- anonymous

which is?

- AriPotta

here i'll use this as an example
y <= -2x + 3
the y-intercept is 3. so the first point you need to plot is (0,3).
the slope is -2. slope is rise/run. so from the point (0,3), go down 2 and over to the right 1, which would be (1,1). plot a point there.
since the inequality is <=, our line is solid. so make a solid line through your two points. shade under the line.

- anonymous

|dw:1363736756403:dw|

- anonymous

something like this?

- AriPotta

yes

- AriPotta

now plot this one on the same graph
y <= x + 3

- anonymous

like add that to the graph i just made?

- AriPotta

yes

- anonymous

|dw:1363737069536:dw|

- AriPotta

why did you make a point there
|dw:1363737269524:dw|

- anonymous

oh. i wasnt sure so i kinda guessed..

- anonymous

@dmezzullo

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