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yashar806
Who can help me with statistics?
Its taking time for me, Sorry 'bout that
Sorry, statistics is out of my area...
Yoou should probably try the statistics section.
it was long ago that i studied stats, try in statistics section
nobody helps me in statistics section
The average should be just (0.15) * 235
@wio 15% of the PEOPLE are lefties, not 15% of the seats
\[ n = 205 \text{ trials (number of students)}\\ p = 0.15 \text{ probability}\\ -\\ \mu = np \text{ mean}\\ \sigma =\sqrt{np(1-p)} \text{ standard deviation} \]
what about the second one
As I said before \(n\) is number of students. \(X\) is number of lefties.
isn't the mean just 15% of 205 ?
yeah i am pretty sure that is what it is. i don't really know any statistics
oh i didn't look @wio wrote the answer above
so how should I find it
find the mean? it is \(.15\times 205=30.75\)
standard deviation is what @wio wrote as well
I don't understand last one
i guess you are to assume that it is normally distributed, so using a normal table find the probability that \(X<27\)
in this case should I use 235 or 205 ? for total?
or rather change to a z score, that is my guess
the 235 is not important. there are 205 students, the mean is \(30.75\) and the standard deviation is about \(5.11\)
\(30.75-27=3.25\) and \(3.25\div 5.11=.636\) approximately, so find the probability using a normal table that \(X<-.636\)
that is my guess anyway, i would not bet any money on it
i need to use that formula
i have no idea what p hat means
so for the n should I use 205?
yes that is \(n\) but i have no idea what p hat means, so i am useless at this point
p hat actually equals to = x/n
I dont understand b first question also c
This is a problem where one can apply the binomial distribution. \[f(k) = \frac{n!}{k!(n-k)!} p^{k} (1-p)^{n-k}\] This is for when there are number of yes/no outcomes. If one yes has probability p for an individual outcome, this formula gives the probability of getting k yes outcomes out of n total outcomes. In this case p would be the probability of a single student being left handed. Now if k students are left handed, the proportion of left handed students is (let's call it y) \[y = k/n\] So what are the mean and variance of this? well to find the mean of the binomial distribution (the mean value of the number of students who are left handed) we'd do \[E[X] =\sum_k k f(k)\] But now we have some proportion k/n, but the probability is the same, f(k) \[E[X/n] =\sum_k \frac{k}{n} f(k) = \frac{1}{n}\sum_k k f(k) = \frac{1}{n}E[X] \]
actaully for the second one we have to use p hat
\[\hat{p} = X/n\] Where X i the number of lefties and n is the total number of students in the class.
can you give me a number? i mean use b as an example?
cuz i dont really know how to find it ?
p hat and X are not the usual kind numbers. They are labels to represent a number which has different probabilities for different values.
For example X = k has the probability f(k) which I gave.
so you mean 27 / 205 ?
did you see question b ?
it asks for mean and standard deviation
In statistics and probability theory, standard deviation (represented by the symbol sigma, σ) shows how much variation or "dispersion" exists from the average (mean), or expected value. A low standard deviation indicates that the data points tend to be very close to the mean; high standard deviation indicates that the data points are spread out over a large range of values. The standard deviation of a random variable, statistical population, data set, or probability distribution is the square root of its variance. It is algebraically simpler though practically less robust than the average absolute deviation.[1][2] A useful property of standard deviation is that, unlike variance, it is expressed in the same units as the data. Note, however, that for measurements with percentage as unit, the standard deviation will have percentage points as unit. In addition to expressing the variability of a population, standard deviation is commonly used to measure confidence in statistical conclusions. For example, the margin of error in polling data is determined by calculating the expected standard deviation in the results if the same poll were to be conducted multiple times. The reported margin of error is typically about twice the standard deviation – the radius of a 95 percent confidence interval. In science, researchers commonly report the standard deviation of experimental data, and only effects that fall far outside the range of standard deviation are considered statistically significant – normal random error or variation in the measurements is in this way distinguished from causal variation. Standard deviation is also important in finance, where the standard deviation on the rate of return on an investment is a measure of the volatility of the investment. When only a sample of data from a population is available, the population standard deviation can be estimated by a modified quantity called the sample standard deviation.
No, I did not mean 27/205. By X I did not mean the number of seats for left handed people. I meant the number of left handed people. There are different probabilities for different numbers of left handed people.
can you solve it ? cuz i cant