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Yes? I think you can cancel out one tan and the x.

Why is Tan squared?

\[\Large \tan x+ \frac{1}{\tan x}=\frac{\tan^2(x)+1}{\tan(x)}\]

getting the same denominator. From Algebra.

Oh okay I see. So I have to simplify now.
And I cancel out one tan therefore making it tan(x)+1/1?

if you cancel out the tan you're left with the LHS of the equation, that's why they are equal.

Did you manage to verify this problem for yourself already?

Yes.

oh very good then!

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