toxicsugar22
  • toxicsugar22
For the following reaction, 6.73 grams of hydrochloric acid are mixed with excess barium hydroxide. The reaction yields 15.5 grams of barium chloride. 2 HCl (aq) + Ba(OH)2 (aq) = BaCl2 (aq) + 2 H2O (l) (1) What is the theoretical yield of barium chloride ? grams (2) What is the percent yield for this reaction ? %
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
step 1. 2 moles HCL -----> 1 mole BeCl2 step 2. find gram molecular wts of HCl and BeCl2
anonymous
  • anonymous
@toxicsugar22 now, express the answer
toxicsugar22
  • toxicsugar22
thsi is my first time doing this so please bear with me

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toxicsugar22
  • toxicsugar22
im just practicing
anonymous
  • anonymous
no problem.. try it. it is fairly easy,...
anonymous
  • anonymous
just answer for step 2.
anonymous
  • anonymous
gram mol weight (gmw) = sum of atmic weights of all the elemnts in the molecule so, gmw of HCl = at. wt. of H + atomic wt. of CL
anonymous
  • anonymous
at. wt. of Cl = ? you have to refer to your Preiodic table
anonymous
  • anonymous
17 is the "atomic number" of Cl and 35.5 is the atomic wt.
toxicsugar22
  • toxicsugar22
1+35
anonymous
  • anonymous
good, so, gmw of HCl = 36.5 what this means is that 1mole of HCl weighs 36.5g (g=grams)
anonymous
  • anonymous
similarly, for BeCl2... notice that there are two atoms of chlorine
anonymous
  • anonymous
sorry it is BaCl2
anonymous
  • anonymous
practice to write it clearly.. gmw of BaCl2 = ___ + ___ + ____ = ____g
toxicsugar22
  • toxicsugar22
sorry I got 137 is the atomic number for Ba and 35 for Cl
anonymous
  • anonymous
no.. atomic number = number of protons in the nucleus of an atom atomic mass number = total number of protons + neutrons in the nucleus of an atom
anonymous
  • anonymous
ok so gmw of BaCl2 = ?
toxicsugar22
  • toxicsugar22
I added the two 137+ 35
anonymous
  • anonymous
good now back to step 2... summarize our values
anonymous
  • anonymous
@toxicsugar22
anonymous
  • anonymous
you see.. those are just numbers.. I cannot help you unless you put meaning to them. gram mol wt of HCL = gram mol wt of BaCl2 =
toxicsugar22
  • toxicsugar22
1mole of HCl weighs 36.5g 1 mole of BaCI2 WEIGHS 172
anonymous
  • anonymous
good.
anonymous
  • anonymous
now, using step 1, 2 moles of HCl ----------- yield ----------> 1mole BaCl2 i.e, 2* gmw of HCL ------------ yields -----------> 1*gmw of BaCl2
anonymous
  • anonymous
follow?
anonymous
  • anonymous
now, put your numbers
anonymous
  • anonymous
2*_ = __ g of HCl ---- > ____g BaCl2
anonymous
  • anonymous
perfecto..
toxicsugar22
  • toxicsugar22
02*36.5 = 73 g of HCl ---- > 172g BaCl2
anonymous
  • anonymous
so, 73g HCl ------> 172g BaCl2 (Theoretical) so, 6.73g HCl -------- should yield how much? (we have 6.73g HCl and Expected BaCl2 is?)
anonymous
  • anonymous
no.. HCl is our "reactant"..... BaCl2 is our product
anonymous
  • anonymous
no
anonymous
  • anonymous
ok, so, 73g HCl ----------- reacts to give us (yield) --------> 173g of BaCl2 how much HCl do we have in our reaction? (this part from the given question)
toxicsugar22
  • toxicsugar22
15.5 is the actual yield
anonymous
  • anonymous
just stay to the point... do not go jumping places.
toxicsugar22
  • toxicsugar22
6.73 is how much HCI WE HAVE
anonymous
  • anonymous
good.
anonymous
  • anonymous
so, if 73g HCl -------- provides -------> 173g BaCl2 then 6.73g HCl --------- should provide -----> ____g of BaCl2 this is a simple ratio..
anonymous
  • anonymous
follow?
anonymous
  • anonymous
STEPS!!!
anonymous
  • anonymous
..... \[{6.73 \times 173 \over 73}=?\]
toxicsugar22
  • toxicsugar22
15.94
anonymous
  • anonymous
ok. but do you understand this?
toxicsugar22
  • toxicsugar22
OK NOW i DO
toxicsugar22
  • toxicsugar22
I had to rethimk the problem
anonymous
  • anonymous
good. then THIS is your theoretical yield i.e., in theory, that 6.73g of HCl should give us with 15.94g of BaCl2
anonymous
  • anonymous
got it?
toxicsugar22
  • toxicsugar22
good thank you for tutoring me
anonymous
  • anonymous
not done yet that is just part (a)
toxicsugar22
  • toxicsugar22
part B. is where we do actual yield times theroicatl yield / 100
toxicsugar22
  • toxicsugar22
is that right
anonymous
  • anonymous
(b) % yield = (actual yield) * 100 / (theoretical yield) this value must be less than 100 actual yield = given in problem theoretical yield = calculated above
toxicsugar22
  • toxicsugar22
ok
toxicsugar22
  • toxicsugar22
so 15.5 times 100/ 15.94 =97.23
anonymous
  • anonymous
yes
toxicsugar22
  • toxicsugar22
ok good
toxicsugar22
  • toxicsugar22
can you go over one more problem with me
toxicsugar22
  • toxicsugar22
you are good tutor for me
toxicsugar22
  • toxicsugar22
just so I get this done evenfurthur
anonymous
  • anonymous
call it a day for today. some other time. keep practicing, put meanings to numbers and write clearly so you see what you are doing
toxicsugar22
  • toxicsugar22
ok thank you for helping me
anonymous
  • anonymous
@toxicsugar22 wtf not even a medal for the pain
toxicsugar22
  • toxicsugar22
soory I forgot

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