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toxicsugar22

  • one year ago

For the following reaction, 6.73 grams of hydrochloric acid are mixed with excess barium hydroxide. The reaction yields 15.5 grams of barium chloride. 2 HCl (aq) + Ba(OH)2 (aq) = BaCl2 (aq) + 2 H2O (l) (1) What is the theoretical yield of barium chloride ? grams (2) What is the percent yield for this reaction ? %

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  1. electrokid
    • one year ago
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    step 1. 2 moles HCL -----> 1 mole BeCl2 step 2. find gram molecular wts of HCl and BeCl2

  2. electrokid
    • one year ago
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    @toxicsugar22 now, express the answer

  3. toxicsugar22
    • one year ago
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    thsi is my first time doing this so please bear with me

  4. toxicsugar22
    • one year ago
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    im just practicing

  5. electrokid
    • one year ago
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    no problem.. try it. it is fairly easy,...

  6. electrokid
    • one year ago
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    just answer for step 2.

  7. electrokid
    • one year ago
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    gram mol weight (gmw) = sum of atmic weights of all the elemnts in the molecule so, gmw of HCl = at. wt. of H + atomic wt. of CL

  8. electrokid
    • one year ago
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    at. wt. of Cl = ? you have to refer to your Preiodic table

  9. electrokid
    • one year ago
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    17 is the "atomic number" of Cl and 35.5 is the atomic wt.

  10. toxicsugar22
    • one year ago
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    1+35

  11. electrokid
    • one year ago
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    good, so, gmw of HCl = 36.5 what this means is that 1mole of HCl weighs 36.5g (g=grams)

  12. electrokid
    • one year ago
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    similarly, for BeCl2... notice that there are two atoms of chlorine

  13. electrokid
    • one year ago
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    sorry it is BaCl2

  14. electrokid
    • one year ago
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    practice to write it clearly.. gmw of BaCl2 = ___ + ___ + ____ = ____g

  15. toxicsugar22
    • one year ago
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    sorry I got 137 is the atomic number for Ba and 35 for Cl

  16. electrokid
    • one year ago
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    no.. atomic number = number of protons in the nucleus of an atom atomic mass number = total number of protons + neutrons in the nucleus of an atom

  17. electrokid
    • one year ago
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    ok so gmw of BaCl2 = ?

  18. toxicsugar22
    • one year ago
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    I added the two 137+ 35

  19. electrokid
    • one year ago
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    good now back to step 2... summarize our values

  20. electrokid
    • one year ago
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    @toxicsugar22

  21. electrokid
    • one year ago
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    you see.. those are just numbers.. I cannot help you unless you put meaning to them. gram mol wt of HCL = gram mol wt of BaCl2 =

  22. toxicsugar22
    • one year ago
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    1mole of HCl weighs 36.5g 1 mole of BaCI2 WEIGHS 172

  23. electrokid
    • one year ago
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    good.

  24. electrokid
    • one year ago
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    now, using step 1, 2 moles of HCl ----------- yield ----------> 1mole BaCl2 i.e, 2* gmw of HCL ------------ yields -----------> 1*gmw of BaCl2

  25. electrokid
    • one year ago
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    follow?

  26. electrokid
    • one year ago
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    now, put your numbers

  27. electrokid
    • one year ago
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    2*_ = __ g of HCl ---- > ____g BaCl2

  28. electrokid
    • one year ago
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    perfecto..

  29. toxicsugar22
    • one year ago
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    02*36.5 = 73 g of HCl ---- > 172g BaCl2

  30. electrokid
    • one year ago
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    so, 73g HCl ------> 172g BaCl2 (Theoretical) so, 6.73g HCl -------- should yield how much? (we have 6.73g HCl and Expected BaCl2 is?)

  31. electrokid
    • one year ago
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    no.. HCl is our "reactant"..... BaCl2 is our product

  32. electrokid
    • one year ago
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    no

  33. electrokid
    • one year ago
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    ok, so, 73g HCl ----------- reacts to give us (yield) --------> 173g of BaCl2 how much HCl do we have in our reaction? (this part from the given question)

  34. toxicsugar22
    • one year ago
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    15.5 is the actual yield

  35. electrokid
    • one year ago
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    just stay to the point... do not go jumping places.

  36. toxicsugar22
    • one year ago
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    6.73 is how much HCI WE HAVE

  37. electrokid
    • one year ago
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    good.

  38. electrokid
    • one year ago
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    so, if 73g HCl -------- provides -------> 173g BaCl2 then 6.73g HCl --------- should provide -----> ____g of BaCl2 this is a simple ratio..

  39. electrokid
    • one year ago
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    follow?

  40. electrokid
    • one year ago
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    STEPS!!!

  41. electrokid
    • one year ago
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    ..... \[{6.73 \times 173 \over 73}=?\]

  42. toxicsugar22
    • one year ago
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    15.94

  43. electrokid
    • one year ago
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    ok. but do you understand this?

  44. toxicsugar22
    • one year ago
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    OK NOW i DO

  45. toxicsugar22
    • one year ago
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    I had to rethimk the problem

  46. electrokid
    • one year ago
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    good. then THIS is your theoretical yield i.e., in theory, that 6.73g of HCl should give us with 15.94g of BaCl2

  47. electrokid
    • one year ago
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    got it?

  48. toxicsugar22
    • one year ago
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    good thank you for tutoring me

  49. electrokid
    • one year ago
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    not done yet that is just part (a)

  50. toxicsugar22
    • one year ago
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    part B. is where we do actual yield times theroicatl yield / 100

  51. toxicsugar22
    • one year ago
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    is that right

  52. electrokid
    • one year ago
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    (b) % yield = (actual yield) * 100 / (theoretical yield) this value must be less than 100 actual yield = given in problem theoretical yield = calculated above

  53. toxicsugar22
    • one year ago
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    ok

  54. toxicsugar22
    • one year ago
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    so 15.5 times 100/ 15.94 =97.23

  55. electrokid
    • one year ago
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    yes

  56. toxicsugar22
    • one year ago
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    ok good

  57. toxicsugar22
    • one year ago
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    can you go over one more problem with me

  58. toxicsugar22
    • one year ago
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    you are good tutor for me

  59. toxicsugar22
    • one year ago
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    just so I get this done evenfurthur

  60. electrokid
    • one year ago
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    call it a day for today. some other time. keep practicing, put meanings to numbers and write clearly so you see what you are doing

  61. toxicsugar22
    • one year ago
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    ok thank you for helping me

  62. electrokid
    • one year ago
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    @toxicsugar22 wtf not even a medal for the pain

  63. toxicsugar22
    • one year ago
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    soory I forgot

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