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For the following reaction, 4.51 grams of iron are mixed with excess oxygen gas. The reaction yields 5.73 grams of iron(III) oxide. 4 Fe (s) + 3 O2 (g) = 2 Fe2O3 (s) (1) What is the theoretical yield of iron(III) oxide ? grams (2) What is the percent yield for this reaction ? %

Chemistry
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4 Fe (s) + 3 O2 (g) ----->2 Fe2O3 (s) 56 *4 grams of Fe react with 3 * 32 grams of O2 to give (4*56 + 6*16) of Fe2O3
So the theoretical yield of iron(III) oxide = 320g = (4*56 + 6*16)
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For the following reaction, 4.77 grams of iron are mixed with excess oxygen gas. The reaction yields 5.71 grams of iron(III) oxide. 4 Fe (s) + 3 O2 (g) =2 Fe2O3 (s) (1) What is the theoretical yield of iron(III) oxide ? grams (2) What is the percent yield for this reaction ?
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