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malibugranprix2000
Group Title
lim_(x>0^+) (x^2/21/x)
How do I figure out this problem?
Find the limit.
 one year ago
 one year ago
malibugranprix2000 Group Title
lim_(x>0^+) (x^2/21/x) How do I figure out this problem? Find the limit.
 one year ago
 one year ago

This Question is Closed

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ x^2 }{ 21/x } = \frac{ x^3 }{ 2x1 }\]
 one year ago

Mamoona_akbar Group TitleBest ResponseYou've already chosen the best response.0
i didn't get your question.
 one year ago

malibugranprix2000 Group TitleBest ResponseYou've already chosen the best response.0
dw:1363774845928:dw
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\large \lim_{x \rightarrow 0^+} \frac{x^2}{2}\frac{1}{x}\]As we approach 0 from the right, our function is approaching \[\large \frac{0}{2}\infty\] Right? :o Since we're on the right side, our x values are all positive. So we end up heading towards negative infinity, due to the subtraction.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Do you understand why \(\large \dfrac{1}{x}\) approaches \(\large \infty\) as \(\large x\) approaches \(\large 0\) from the right? That's kinda important to understand with these types of problems. c:
 one year ago

malibugranprix2000 Group TitleBest ResponseYou've already chosen the best response.0
@zepdrix your explanation is clear, thanks.
 one year ago
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