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malibugranprix2000

  • 2 years ago

lim_(x->0^+) (x^2/2-1/x) How do I figure out this problem? Find the limit.

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  1. Yahoo!
    • 2 years ago
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    \[\frac{ x^2 }{ 2-1/x } = \frac{ x^3 }{ 2x-1 }\]

  2. Mamoona_akbar
    • 2 years ago
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    i didn't get your question.

  3. malibugranprix2000
    • 2 years ago
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    |dw:1363774845928:dw|

  4. zepdrix
    • 2 years ago
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    \[\large \lim_{x \rightarrow 0^+} \frac{x^2}{2}-\frac{1}{x}\]As we approach 0 from the right, our function is approaching \[\large \frac{0}{2}-\infty\] Right? :o Since we're on the right side, our x values are all positive. So we end up heading towards negative infinity, due to the subtraction.

  5. zepdrix
    • 2 years ago
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    Do you understand why \(\large \dfrac{1}{x}\) approaches \(\large \infty\) as \(\large x\) approaches \(\large 0\) from the right? That's kinda important to understand with these types of problems. c:

  6. malibugranprix2000
    • 2 years ago
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    @zepdrix your explanation is clear, thanks.

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