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DLS

  • 3 years ago

sinx+cosecx=2 sin^8x+cosec^8x=?

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  1. DLS
    • 3 years ago
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    A better method than binomial expansion? :/

  2. DLS
    • 3 years ago
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    i got it :)

  3. Yahoo!
    • 3 years ago
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    sinx + 1/sinx = 2 sin^2 x +1 = 2sinx sin^2x - 2sinx + 1 = 0 Use Quadratic Formula to find the value of sinx

  4. DLS
    • 3 years ago
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    no use of quadratic formula..it is simply (sinx-1)^2=0 sinx=1 ....)

  5. Yahoo!
    • 3 years ago
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    Any how

  6. DLS
    • 3 years ago
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    :)

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