DLS
sinx+cosecx=2
sin^8x+cosec^8x=?



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A better method than binomial expansion? :/

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i got it :)

Yahoo!
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sinx + 1/sinx = 2
sin^2 x +1 = 2sinx
sin^2x  2sinx + 1 = 0
Use Quadratic Formula to find the value of sinx

DLS
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no use of quadratic formula..it is simply
(sinx1)^2=0
sinx=1 ....)

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Any how

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:)