Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Tutorial on finding the Centroid/Center of mass of a complex object. UNISA Students come here.

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

In this tutorial we will find the Centroid about this complex extruded shape. All cutout pieces shall be taken as negative.|dw:1363796078055:dw|
Split the complex shape into its component shapes.|dw:1363796223427:dw|

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Find the area of each of these simple shapes.\[A1 = \frac{ 1 }{ 2 }B \times \tau H\]\[A2 = L \times B\]\[A3 = L x B\]\[A4 = L x B\]
\[A1 = 10m ^{2}\]\[A2 = 20m ^{2}\]\[A3 = 7.5m ^{2}\]\[A4 = 2m ^{2}\] The total are of these 4 will be \[AT = 39.5m ^{2}\]
Now if we take the origional drawing we see that the shapes are in very definate places, and they are at definate points above and away from the x and y axis.|dw:1363796713376:dw|
To determine the centroid of each shame we must include these distances from the axis as well. So for example the y and x centroid of the cut out square in the center will be. \[y _{Cutout} = \frac{ 3m }{ 2 } + 2m\]\[y_{Cutout} = 3.5m\] \[x_{Cutout} = \frac{ 2.5m }{ 2 } + 0.5m\]\[x_{Cutout} = 1.75m\]
yust to make sure|dw:1363797121334:dw|
so we include those formula for the cutout!!!!!
The centroid of the triangular shape will thus be.\[y_{Triangle} = \frac{ 5m }{ 2 } + 2m\]\[y_{Triangle} = 4.5m\] \[x_{Triangle} = \frac{ 2m }{ 2 } + 5m\]\[x_{Triangle} = 6m\]The centroid of the large rectangle will be\[y_{LRec} = \frac{ 5m }{ 2 } + 2m\]\[y_{LRec} = 4.5m\] \[x_{LRec} = \frac{ 4m }{ 2 }\]\[x_{LRec} = 2m\] The centroid of the small rectangle is\[y_{sRec} = \frac{ 2m }{ 2 }\]\[y_{sRec} = 1m\] \[x_{sRec} = \frac{ 1m }{ 2 }\]\[x_{sRec} = 0.5m\]
yes jores we do, we wer not doing that at UNISA, the textbook did not include that piece of information. You have to find the centroid of the shape and add it to the distance from the x or y axis.
So now the final equation to find the centroid of the complex shape will be\[Ay_{Complex}=\frac{ A1y_{Triangle}+A2y_{LRec}−A3y_{Cutout}+A4y_{sRec}}{ AT } \]\[Ax_{Complex}=\frac{ A1x_{Triangle}+A2x_{LRec}−A3x_{Cutout}+A4x_{sRec}}{ AT } \]we minus A3 as it is the cutout shape and therefore is not actually there. The numerical values are as such.\[Ay_{Complex}=\frac{ (10)(4.5)+(20)(4.5)−(7.5)(3.5)+(2)(1) }{ 39.5 }\]\[Ay_{Complex}= 2.80m\] \[Ax_{Complex}=\frac{ (10)(6)+(20)(2)−(7.5)(1.75)+(2)(0.5) }{ 39.5 }\]\[Ax_{Complex}= 2.22m\]
To conclude it will be so.|dw:1363798358172:dw|
Questions are free now.
Don't forget to drop a medal in the box on your way out if you think this helped you? Also don't be afraid to fan me as well.
where did you get this formula yCutout=3m2+2m
I found it while looking on the internet. it is the centroid of the cutout area being 3m over 2 to find the centroid + the distance from the edge of the cutout closest to the y axis to the axis its self. You follow? Should I draw it?
and sorry for my poor spelling i was typing in a rush. It must not be shame it must be shape. I also mistyped just as yust.
oh ok
thanx sheldont i get it

Not the answer you are looking for?

Search for more explanations.

Ask your own question