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tmybby

  • one year ago

Help?? What are the vertex and the axis of symmetry of the equation? y = –2x2 + 8x – 18 a. vertex: ( 2, –10) axis of symmetry: x = 2 b. vertex: (2, –10) axis of symmetry: x = –10 c. vertex: (–2, –10) axis of symmetry: x = –2 d. vertex: (–2, 10) axis of symmetry: y = –2

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  1. satellite73
    • one year ago
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    \[y=ax^2+bx+c\] \[ y = –2x^2 + 8x – 18\] first coordinate of the vertex is always \(-\frac{b}{2a}\) in your case it is \(-\frac{8}{2\times (-2)}=2\)

  2. satellite73
    • one year ago
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    second coordinate is what you get if you replace \(x\) by \(2\)

  3. tmybby
    • one year ago
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    oh ok so it's A?

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