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aajugdarBest ResponseYou've already chosen the best response.1
split 128 in such a way that you can get a complete square like in last problem 9 was square of 3 thats why 63=9*7
 one year ago

SandeepReddyBest ResponseYou've already chosen the best response.1
\[\sqrt{128x^{5}y^2}\] 128 can be divided as 2*64 or \[2*8^{2}\] and x^5 as \[(x^2)^2*x\]
 one year ago

SandeepReddyBest ResponseYou've already chosen the best response.1
So\[\sqrt{2*8^2*(x^2)^2*x*y^2}\]
 one year ago

miahBest ResponseYou've already chosen the best response.0
^^^ thats the answer ? im so confused
 one year ago

aajugdarBest ResponseYou've already chosen the best response.1
4 and 8? no see sandeep solved it there
 one year ago

aajugdarBest ResponseYou've already chosen the best response.1
no thats not the answer
 one year ago

aajugdarBest ResponseYou've already chosen the best response.1
you take complete square terms outside like 64 = 8^2 when you take it out of root you get 8
 one year ago

aajugdarBest ResponseYou've already chosen the best response.1
when you take y^2 out of root you get y
 one year ago

aajugdarBest ResponseYou've already chosen the best response.1
and when you take x^4 out of root you get x^2
 one year ago

SandeepReddyBest ResponseYou've already chosen the best response.1
we have a relation \[\sqrt{a*b*c} = \sqrt{a}*\sqrt{b}*\sqrt{c}\]
 one year ago

SandeepReddyBest ResponseYou've already chosen the best response.1
\[\sqrt{2*8^2*(x^2)^2*x*y^2}\] = \[\sqrt{2}*\sqrt{8^2}*\sqrt{(x^2)^2}*\sqrt{x}*\sqrt{y^2}\]
 one year ago

SandeepReddyBest ResponseYou've already chosen the best response.1
that gives u \[\sqrt{2}*8*x^2*\sqrt{x}*y\]
 one year ago

SandeepReddyBest ResponseYou've already chosen the best response.1
\[8\sqrt{2}x^{3/2}y\]
 one year ago

SandeepReddyBest ResponseYou've already chosen the best response.1
@miah did u get it?
 one year ago

aajugdarBest ResponseYou've already chosen the best response.1
hmm could hv been easier to teach face to face answer is \[8x^2y \sqrt{2xy}\]
 one year ago

SandeepReddyBest ResponseYou've already chosen the best response.1
Yes i too feel same @aajugdar
 one year ago

miahBest ResponseYou've already chosen the best response.0
Yes it would have been easier. But i some what get it.
 one year ago

aajugdarBest ResponseYou've already chosen the best response.1
smwhat is better than nothing
 one year ago
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