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aajugdar
 one year ago
Best ResponseYou've already chosen the best response.1split 128 in such a way that you can get a complete square like in last problem 9 was square of 3 thats why 63=9*7

SandeepReddy
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{128x^{5}y^2}\] 128 can be divided as 2*64 or \[2*8^{2}\] and x^5 as \[(x^2)^2*x\]

SandeepReddy
 one year ago
Best ResponseYou've already chosen the best response.1So\[\sqrt{2*8^2*(x^2)^2*x*y^2}\]

miah
 one year ago
Best ResponseYou've already chosen the best response.0^^^ thats the answer ? im so confused

aajugdar
 one year ago
Best ResponseYou've already chosen the best response.14 and 8? no see sandeep solved it there

aajugdar
 one year ago
Best ResponseYou've already chosen the best response.1no thats not the answer

aajugdar
 one year ago
Best ResponseYou've already chosen the best response.1you take complete square terms outside like 64 = 8^2 when you take it out of root you get 8

aajugdar
 one year ago
Best ResponseYou've already chosen the best response.1when you take y^2 out of root you get y

aajugdar
 one year ago
Best ResponseYou've already chosen the best response.1and when you take x^4 out of root you get x^2

SandeepReddy
 one year ago
Best ResponseYou've already chosen the best response.1we have a relation \[\sqrt{a*b*c} = \sqrt{a}*\sqrt{b}*\sqrt{c}\]

SandeepReddy
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{2*8^2*(x^2)^2*x*y^2}\] = \[\sqrt{2}*\sqrt{8^2}*\sqrt{(x^2)^2}*\sqrt{x}*\sqrt{y^2}\]

SandeepReddy
 one year ago
Best ResponseYou've already chosen the best response.1that gives u \[\sqrt{2}*8*x^2*\sqrt{x}*y\]

SandeepReddy
 one year ago
Best ResponseYou've already chosen the best response.1\[8\sqrt{2}x^{3/2}y\]

SandeepReddy
 one year ago
Best ResponseYou've already chosen the best response.1@miah did u get it?

aajugdar
 one year ago
Best ResponseYou've already chosen the best response.1hmm could hv been easier to teach face to face answer is \[8x^2y \sqrt{2xy}\]

SandeepReddy
 one year ago
Best ResponseYou've already chosen the best response.1Yes i too feel same @aajugdar

miah
 one year ago
Best ResponseYou've already chosen the best response.0Yes it would have been easier. But i some what get it.

aajugdar
 one year ago
Best ResponseYou've already chosen the best response.1smwhat is better than nothing
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