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anonymous
 3 years ago
what is the simplest form of √128x^5y^2
anonymous
 3 years ago
what is the simplest form of √128x^5y^2

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0split 128 in such a way that you can get a complete square like in last problem 9 was square of 3 thats why 63=9*7

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{128x^{5}y^2}\] 128 can be divided as 2*64 or \[2*8^{2}\] and x^5 as \[(x^2)^2*x\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So\[\sqrt{2*8^2*(x^2)^2*x*y^2}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0^^^ thats the answer ? im so confused

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.04 and 8? no see sandeep solved it there

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no thats not the answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you take complete square terms outside like 64 = 8^2 when you take it out of root you get 8

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0when you take y^2 out of root you get y

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and when you take x^4 out of root you get x^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we have a relation \[\sqrt{a*b*c} = \sqrt{a}*\sqrt{b}*\sqrt{c}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{2*8^2*(x^2)^2*x*y^2}\] = \[\sqrt{2}*\sqrt{8^2}*\sqrt{(x^2)^2}*\sqrt{x}*\sqrt{y^2}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that gives u \[\sqrt{2}*8*x^2*\sqrt{x}*y\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[8\sqrt{2}x^{3/2}y\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmm could hv been easier to teach face to face answer is \[8x^2y \sqrt{2xy}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes i too feel same @aajugdar

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes it would have been easier. But i some what get it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0smwhat is better than nothing
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