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anonymous
 3 years ago
Joe has 4 red pens, 1 green pen, 2 blue pens, and 3 black pens.
What is the probability he will randomly select a black pen and then,without replacing it, randomly selecti a blue pen?
anonymous
 3 years ago
Joe has 4 red pens, 1 green pen, 2 blue pens, and 3 black pens. What is the probability he will randomly select a black pen and then,without replacing it, randomly selecti a blue pen?

This Question is Closed

aripotta
 3 years ago
Best ResponseYou've already chosen the best response.0OH I'M SORRY. I'M NOT GOOD WITH PROBABILITY

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.1P(Black) = 3/10 P(Blue) = 2/9 multiply of both

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0event A: selecting "1" black from a total of (4+1+2+3)=10; \[P(A)={3\over10}\] event B: selecting "1" blue from the remainning "9" \[P(B)={2\over9}\] now, the events are mutually independent... \[P(A\cap B)=P(A)\times P(B)={3\over10}\times{2\over9}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0IDK who to give BEST ANSWER to. LOL.
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