Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

help123please.

  • 3 years ago

Joe has 4 red pens, 1 green pen, 2 blue pens, and 3 black pens. What is the probability he will randomly select a black pen and then,without replacing it, randomly selecti a blue pen?

  • This Question is Closed
  1. help123please.
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @AriPotta

  2. AriPotta
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    OH I'M SORRY. I'M NOT GOOD WITH PROBABILITY

  3. help123please.
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ITS OK ARI

  4. RadEn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    P(Black) = 3/10 P(Blue) = 2/9 multiply of both

  5. electrokid
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    event A: selecting "1" black from a total of (4+1+2+3)=10; \[P(A)={3\over10}\] event B: selecting "1" blue from the remainning "9" \[P(B)={2\over9}\] now, the events are mutually independent... \[P(A\cap B)=P(A)\times P(B)={3\over10}\times{2\over9}\]

  6. help123please.
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Oh, ok, thanks!

  7. help123please.
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    IDK who to give BEST ANSWER to. LOL.

  8. electrokid
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

  9. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy