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Joe has 4 red pens, 1 green pen, 2 blue pens, and 3 black pens.
What is the probability he will randomly select a black pen and then,without replacing it, randomly selecti a blue pen?
 one year ago
 one year ago
Joe has 4 red pens, 1 green pen, 2 blue pens, and 3 black pens. What is the probability he will randomly select a black pen and then,without replacing it, randomly selecti a blue pen?
 one year ago
 one year ago

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AriPottaBest ResponseYou've already chosen the best response.0
OH I'M SORRY. I'M NOT GOOD WITH PROBABILITY
 one year ago

RadEnBest ResponseYou've already chosen the best response.1
P(Black) = 3/10 P(Blue) = 2/9 multiply of both
 one year ago

electrokidBest ResponseYou've already chosen the best response.2
event A: selecting "1" black from a total of (4+1+2+3)=10; \[P(A)={3\over10}\] event B: selecting "1" blue from the remainning "9" \[P(B)={2\over9}\] now, the events are mutually independent... \[P(A\cap B)=P(A)\times P(B)={3\over10}\times{2\over9}\]
 one year ago

help123please.Best ResponseYou've already chosen the best response.0
Oh, ok, thanks!
 one year ago

help123please.Best ResponseYou've already chosen the best response.0
IDK who to give BEST ANSWER to. LOL.
 one year ago
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