## anonymous 3 years ago Joe has 4 red pens, 1 green pen, 2 blue pens, and 3 black pens. What is the probability he will randomly select a black pen and then,without replacing it, randomly selecti a blue pen?

1. anonymous

@AriPotta

2. anonymous

OH I'M SORRY. I'M NOT GOOD WITH PROBABILITY

3. anonymous

ITS OK ARI

P(Black) = 3/10 P(Blue) = 2/9 multiply of both

5. anonymous

event A: selecting "1" black from a total of (4+1+2+3)=10; $P(A)={3\over10}$ event B: selecting "1" blue from the remainning "9" $P(B)={2\over9}$ now, the events are mutually independent... $P(A\cap B)=P(A)\times P(B)={3\over10}\times{2\over9}$

6. anonymous

Oh, ok, thanks!

7. anonymous

IDK who to give BEST ANSWER to. LOL.

8. anonymous