anonymous
  • anonymous
Joe has 4 red pens, 1 green pen, 2 blue pens, and 3 black pens. What is the probability he will randomly select a black pen and then,without replacing it, randomly selecti a blue pen?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@AriPotta
AriPotta
  • AriPotta
OH I'M SORRY. I'M NOT GOOD WITH PROBABILITY
anonymous
  • anonymous
ITS OK ARI

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

RadEn
  • RadEn
P(Black) = 3/10 P(Blue) = 2/9 multiply of both
anonymous
  • anonymous
event A: selecting "1" black from a total of (4+1+2+3)=10; \[P(A)={3\over10}\] event B: selecting "1" blue from the remainning "9" \[P(B)={2\over9}\] now, the events are mutually independent... \[P(A\cap B)=P(A)\times P(B)={3\over10}\times{2\over9}\]
anonymous
  • anonymous
Oh, ok, thanks!
anonymous
  • anonymous
IDK who to give BEST ANSWER to. LOL.
anonymous
  • anonymous

Looking for something else?

Not the answer you are looking for? Search for more explanations.