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help123please.

  • 2 years ago

Based on the following results what is the experimental probability of rolling a 1? Outcome Frequency 1 6 2 2 3 2 4 3 5 2 6 0

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  1. help123please.
    • 2 years ago
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    @garrett_payne

  2. wio
    • 2 years ago
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    Add up all the frequencies. Divide the frequency of the target outcome by the sum of all frequencies.

  3. help123please.
    • 2 years ago
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    let me try..

  4. help123please.
    • 2 years ago
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    so add up 1-6/6?

  5. wio
    • 2 years ago
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    No.. divide 6 by 6+2+2+3+...

  6. help123please.
    • 2 years ago
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    I know. 1-6 means all the numbers between 0 and 6.

  7. help123please.
    • 2 years ago
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    1+2+3+4+5+6/6

  8. help123please.
    • 2 years ago
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    ?

  9. wio
    • 2 years ago
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    divide x by y means x / y not y / x

  10. help123please.
    • 2 years ago
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    I got '16'.

  11. wio
    • 2 years ago
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    It makes no sense for probability to be over 1.

  12. help123please.
    • 2 years ago
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    wait,sorry.

  13. help123please.
    • 2 years ago
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    can you give me the equation?

  14. help123please.
    • 2 years ago
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    o wait, you mean 6/1+2+3+4+5+6 ?

  15. electrokid
    • 2 years ago
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    probability of an event A happening in N number of experiments: \[P(A)=\frac{\text{number of times A event happens}}{N}\]

  16. help123please.
    • 2 years ago
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    so - what would the numerator be?

  17. electrokid
    • 2 years ago
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    event = the dice rolls a "1" how many times does that happen?

  18. help123please.
    • 2 years ago
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    6.

  19. electrokid
    • 2 years ago
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    bingo

  20. help123please.
    • 2 years ago
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    oooh.

  21. electrokid
    • 2 years ago
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    :)

  22. help123please.
    • 2 years ago
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    tyty!

  23. help123please.
    • 2 years ago
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    and the denominator is

  24. help123please.
    • 2 years ago
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    6. right?

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