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BrianWest

  • 3 years ago

help solving polinomial equations

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  1. BrianWest
    • 3 years ago
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    \[x ^{3}+216=0\]

  2. Mertsj
    • 3 years ago
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    1. Subtract 216 from both sides 2. Take the third root of both sides.

  3. BrianWest
    • 3 years ago
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    what does it look like worked out, i am confused

  4. inkyvoyd
    • 3 years ago
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    Now now, don't you go human wolframing without giving the answer. ;)

  5. Mertsj
    • 3 years ago
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    Can you subtract 216 from both sides?

  6. BrianWest
    • 3 years ago
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    yes, i get x^3=-216

  7. Mertsj
    • 3 years ago
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    Do you know what a third root is?

  8. Mertsj
    • 3 years ago
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    For example, the third root of 8 is 2 because 2 raised to the third power is 8

  9. BrianWest
    • 3 years ago
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    yes, the thierd root of 216=6 x=6

  10. Mertsj
    • 3 years ago
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    |dw:1363827771232:dw|

  11. Mertsj
    • 3 years ago
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    What is the third root of -216?

  12. BrianWest
    • 3 years ago
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    -6i

  13. BrianWest
    • 3 years ago
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    -6 or 6i

  14. Mertsj
    • 3 years ago
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    Just plain -6 because -6 x -6 x -6 = -216

  15. BrianWest
    • 3 years ago
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    so my answer is -6... correct

  16. Mertsj
    • 3 years ago
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    Correct. Very good.

  17. BrianWest
    • 3 years ago
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    please help,how do you work. confused. if p(x)=3x^2x+5 and r(x)=x^3 +x+1, find each value.. problem: 4p(a)

  18. Mertsj
    • 3 years ago
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    Find the p(a) be replacing each x with a Find 4p(a) by multiplying that result by 4

  19. BrianWest
    • 3 years ago
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    i have p(a) = 3a^2 -2a +5

  20. BrianWest
    • 3 years ago
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    my final answer is 4p(a) = 45 is this correct???

  21. BrianWest
    • 3 years ago
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    is this correct

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