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help solving polinomial equations

Algebra
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\[x ^{3}+216=0\]
1. Subtract 216 from both sides 2. Take the third root of both sides.
what does it look like worked out, i am confused

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Other answers:

Now now, don't you go human wolframing without giving the answer. ;)
Can you subtract 216 from both sides?
yes, i get x^3=-216
Do you know what a third root is?
For example, the third root of 8 is 2 because 2 raised to the third power is 8
yes, the thierd root of 216=6 x=6
|dw:1363827771232:dw|
What is the third root of -216?
-6i
-6 or 6i
Just plain -6 because -6 x -6 x -6 = -216
so my answer is -6... correct
Correct. Very good.
please help,how do you work. confused. if p(x)=3x^2x+5 and r(x)=x^3 +x+1, find each value.. problem: 4p(a)
Find the p(a) be replacing each x with a Find 4p(a) by multiplying that result by 4
i have p(a) = 3a^2 -2a +5
my final answer is 4p(a) = 45 is this correct???
is this correct

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