BrianWest
help solving polinomial equations



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BrianWest
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\[x ^{3}+216=0\]

Mertsj
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1. Subtract 216 from both sides
2. Take the third root of both sides.

BrianWest
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what does it look like worked out, i am confused

inkyvoyd
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Now now, don't you go human wolframing without giving the answer. ;)

Mertsj
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Can you subtract 216 from both sides?

BrianWest
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yes, i get x^3=216

Mertsj
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Do you know what a third root is?

Mertsj
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For example, the third root of 8 is 2 because 2 raised to the third power is 8

BrianWest
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yes, the thierd root of 216=6
x=6

Mertsj
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dw:1363827771232:dw

Mertsj
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What is the third root of 216?

BrianWest
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6i

BrianWest
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6 or 6i

Mertsj
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Just plain 6 because 6 x 6 x 6 = 216

BrianWest
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so my answer is 6... correct

Mertsj
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Correct. Very good.

BrianWest
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please help,how do you work. confused.
if p(x)=3x^2x+5 and r(x)=x^3 +x+1, find each value..
problem: 4p(a)

Mertsj
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Find the p(a) be replacing each x with a
Find 4p(a) by multiplying that result by 4

BrianWest
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i have p(a) = 3a^2 2a +5

BrianWest
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my final answer is 4p(a) = 45
is this correct???

BrianWest
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is this correct