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LovingMyselfBest ResponseYou've already chosen the best response.0
whats the question
 one year ago

wildBest ResponseYou've already chosen the best response.0
write each expression so that it contains only positive exponents
 one year ago

LovingMyselfBest ResponseYou've already chosen the best response.0
I dunno this 1 im so sorry
 one year ago

satellite73Best ResponseYou've already chosen the best response.3
\[\frac{(3x)^{1}}{ 4}=\frac{1}{4(3x)}\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.3
\(b^{1}=\frac{1}{b}\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.3
in general, \[b^{n}=\frac{1}{b^n}\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.3
i picked \(b\) as a variable you can use anyone you prefer
 one year ago

wildBest ResponseYou've already chosen the best response.0
satellite are you there:(
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
I don't know what else there is to say. What don't you understand?
 one year ago

wildBest ResponseYou've already chosen the best response.0
idk i just dont know how to do it
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
This is what your problem looks like, right? \[\frac{ (3x)^{1} }{ 4 }\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
This is what your problem looks like, right? \[\frac{ (3x)^{1} }{ 4 }\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
Did you know that \[x^{1}=\frac{ 1 }{ x }\]?
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
Same thing. \[x^1=x\] just like \[3^{1}=3\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
One thing first. Whenever you want to say that x has an exponential value of 1, you should type x^1 or x to the power of 1 rather than x1 because x1 is just subtraction.
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
Is this what you're saying?\[x^{1}=\frac{ 1 }{ x^{1} }\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
Then you are right. But, as I said, \[x^{1}=x\] So you can just change the \[x^{1}\] to \[x\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
This means that \[x^{−1}=\frac{ 1 }{ x }\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
Rewrite this so that there are only positive exponents:\[\frac{ 1 }{ x^{1} }\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
No. General rule of thumb. If you see a negative number as an exponent, flip the term(with the exponent) over the fraction bar and make the exponent positive
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
so I flip x^1 over to the numerator and get \[x^{1}\] then I take away the negative sign which gets me \[x^{1}\] or \[x\]
 one year ago

wildBest ResponseYou've already chosen the best response.0
so every time there an equation like this \[1 \over x ^1\] you have to flip
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
Yes. But ONLY if the exponent is negative. Next problem:\[\frac{ 1 }{ x^{2} }\]
 one year ago

wildBest ResponseYou've already chosen the best response.0
so I fliped x^21 over to the numerator and get x−2 then I take away the negative sign which gets me x2
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
x^2 is right. Next one:\[x ^{3}\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
I think it's a silly mistake, but it was x^3, not x^2
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
Might be because the number was so small.
 one year ago

wildBest ResponseYou've already chosen the best response.0
oh yeah it was a little as i looked closer it was a 3
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
Next one(and the important one to help you with your problem):\[\frac{ 4 }{ x^{2} }\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
Why don't you bring x^2 to the numerator and take away the negative sign?
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
Exactly. Now can you do this?\[\frac{ (3x)^{1} }{ 4 }\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
If you really don't understand, no is a good answer too.
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
remember what we did with \[x^{2}\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
We flipped it into the denominator and took away the negative sign to get \[\frac{ 1 }{ x^{2} }\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
Can you apply this to your problem or should I just explain?
 one year ago

wildBest ResponseYou've already chosen the best response.0
but 3 is a numerator too it can turn to 1
 one year ago

wildBest ResponseYou've already chosen the best response.0
yeah you should explain i get everything you taught me i just can put it all together
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
Do you agree that \[(3x)^{1}=\frac{ 1 }{ (3x)^{1} }\]or \[\frac{ 1 }{ (3x) }\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
Errr I mean that it equals both but the lower one without the exponent of 1 is simplified
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
But you agree with it, right?
 one year ago

wildBest ResponseYou've already chosen the best response.0
i should've looked at it as a whole
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
Now do you agree that \[(3x)^{−1}\times \frac{ 1 }{ 4 }=\frac{ (3x)^{−1} }{ 4 }\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
so if you substitute the (3x)^1 with \[\frac{ 1 }{ 3x}\] in the expression, you get \[\frac{ 1 }{ 4(3x) }\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
and that simplifies to\[\frac{ 1 }{ 12x }\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
But if you think about it, all I actually did was flip the (3x)^1 over to the denominator and take away the negative signdw:1363833108473:dw
 one year ago

wildBest ResponseYou've already chosen the best response.0
is it the same thing as multiplying 1/3x and 1/4
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
Yes, but the point is that I just flipped it over and that it's incredibly simple.
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
Everyone else does it like:dw:1363833370136:dw
 one year ago

wildBest ResponseYou've already chosen the best response.0
you know what your right its really easy well thank you very much i truly get thank you very much you should be a teacher and again thank you very much 100x:)
 one year ago

GrazesBest ResponseYou've already chosen the best response.2
lolwut. Just understand it. and REMEMBER IT.
 one year ago

wildBest ResponseYou've already chosen the best response.0
hahahadont make me take out my shoe
 one year ago
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