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miah

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  • one year ago
  • one year ago

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  1. miah
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    \[10\sqrt[4]{6} + 4\sqrt[3]{6} - 9\sqrt[3]{6} - 3\sqrt[4]{6}\]

    • one year ago
  2. miah
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    @jim_thompson5910

    • one year ago
  3. jim_thompson5910
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    What are the common terms here

    • one year ago
  4. miah
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    \[10\sqrt[4]{6} and 3\sqrt[4]{6}\]

    • one year ago
  5. miah
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    \[4\sqrt[3]{6} and 9\sqrt[3]{6}\]

    • one year ago
  6. jim_thompson5910
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    good, so combine those pairs of like terms

    • one year ago
  7. jim_thompson5910
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    for example, \(\large 10\sqrt[4]{6}\) and \(\large -3\sqrt[4]{6}\) combine to \(\large 10\sqrt[4]{6} -3\sqrt[4]{6}\) \(\large (10 -3)\sqrt[4]{6}\) \(\large 7\sqrt[4]{6}\)

    • one year ago
  8. jim_thompson5910
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    how about the other pair of terms? what do they combine to?

    • one year ago
  9. miah
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    \[-5\sqrt[3]{6}\]

    • one year ago
  10. miah
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    so the answer is \[7\sqrt[4]{6} - 5\sqrt[3]{6}\]

    • one year ago
  11. miah
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    @jim_thompson5910

    • one year ago
  12. jim_thompson5910
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    good you got it

    • one year ago
  13. miah
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    what about 2√6 ?

    • one year ago
  14. miah
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    whats also an answer choice.

    • one year ago
  15. jim_thompson5910
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    you want to simplify this?

    • one year ago
  16. miah
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    Well it has what i said then my bf said 2√6 and thats also an answer choice.

    • one year ago
  17. jim_thompson5910
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    oh no it's \[7\sqrt[4]{6} - 5\sqrt[3]{6}\] like you said

    • one year ago
  18. miah
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    I have another if you dont mind @jim_thompson5910

    • one year ago
  19. miah
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    \[\sqrt{10} (4-\sqrt{5}) + \sqrt{8} (\sqrt{5}+2)\]

    • one year ago
  20. jim_thompson5910
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    \[\Large \sqrt{10} (4-\sqrt{5}) + \sqrt{8} (\sqrt{5}+2)\] \[\Large \sqrt{10} (4)-\sqrt{10} \sqrt{5} + \sqrt{8}\sqrt{5}+\sqrt{8}(2)\] \[\Large 4\sqrt{10}-\sqrt{10*5} + \sqrt{8*5}+2\sqrt{8}\] \[\Large 4\sqrt{10}-\sqrt{50} + \sqrt{40}+2\sqrt{8}\] \[\Large 4\sqrt{10}-\sqrt{25*2} + \sqrt{4*10}+2\sqrt{4*2}\] \[\Large 4\sqrt{10}-\sqrt{25}*\sqrt{2} + \sqrt{4}*\sqrt{10}+2\sqrt{4}\sqrt{2}\] \[\Large 4\sqrt{10}-5\sqrt{2} + 2\sqrt{10}+2*2\sqrt{2}\] \[\Large 4\sqrt{10}-5\sqrt{2} + 2\sqrt{10}+4\sqrt{2}\] \[\Large 6\sqrt{10}-\sqrt{2}\]

    • one year ago
  21. miah
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    Thank youuu!

    • one year ago
  22. jim_thompson5910
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    yw

    • one year ago
  23. miah
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    \[\frac{ 2 }{ 6-\sqrt{3} } \]

    • one year ago
  24. miah
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    Last one i Promise. lol

    • one year ago
  25. miah
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    @jim_thompson5910

    • one year ago
  26. jim_thompson5910
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    multiply top and bottom by \(\Large 6+\sqrt{3}\) and tell me what you get

    • one year ago
  27. miah
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    12 over √ 3

    • one year ago
  28. jim_thompson5910
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    no you should get this

    • one year ago
  29. jim_thompson5910
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    \[\Large \frac{ 2 }{ 6-\sqrt{3} } \] \[\Large \frac{ 2(6+\sqrt{3}) }{ (6-\sqrt{3})(6+\sqrt{3}) } \] \[\Large \frac{ 2(6+\sqrt{3}) }{ 6^2 - \left(\sqrt{3}\right)^2 } \] \[\Large \frac{ 2(6+\sqrt{3}) }{ 36 - 3 } \] \[\Large \frac{ 2(6+\sqrt{3}) }{ 33 } \] \[\Large \frac{ 12+2\sqrt{3} }{ 33 } \]

    • one year ago
  30. miah
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    Thanks!

    • one year ago
  31. jim_thompson5910
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    np

    • one year ago
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