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satellite73
 one year ago
Best ResponseYou've already chosen the best response.1first write it all out, then factor the numbers that are not prime

mathsucksalot123
 one year ago
Best ResponseYou've already chosen the best response.0wouldn't u factor the numbers that are prime

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1you cannot factor a prime number that is why it is called prime

mathsucksalot123
 one year ago
Best ResponseYou've already chosen the best response.0so ur saying the answer is all of the composite numbers? what?

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1start with \[11\times 10\times 9\times 8\times 7\times 6\times 5\times 4\times 3\times 2\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1then factor the numbers that can be factored, like for example \(10=5\times 2\)

mathsucksalot123
 one year ago
Best ResponseYou've already chosen the best response.0so it would be 2,3,4,5

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1something like the second one

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1you have a lot more work to do you have to factor all the numbers that you can

mathsucksalot123
 one year ago
Best ResponseYou've already chosen the best response.0i think i did...i showed the work on my paper

electrokid
 one year ago
Best ResponseYou've already chosen the best response.0\[11!=2^\text{number of even terms +1}\times3^\text{number of terms divisible by 3+1}\\ \qquad\times5^\text{no. of terms divisible by 5}\times7^{1}\times11^{1}\]

electrokid
 one year ago
Best ResponseYou've already chosen the best response.0so, \[11!=2^8\times3^4\times5^2\times7\times11\]

mathsucksalot123
 one year ago
Best ResponseYou've already chosen the best response.0thanks, i got it
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