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Pandalover485
Help !!get medal
Write an expression to describe a rule for the sequence. Then find the 100th term in the sequence. 4, 9, 14, 19, 24, 29, . . . (1 point) n + 5; 504 5n − 1; 499 5n; 500 4n + 5; 405
Do u see that every next number in the sequence exceeds its previous value a constant number??
I mean if we know the first term in the sequence and add some number to the first number to get the second number that same number when added to (lets say) third term gives you 4th term!
this kind of sequence, we call it Arithmetic Progression or AP series now in this sequence we have a general term for finding nth term which you must remember ( if you want proof i can provide but knowing proof , you must byheart the formula ) |dw:1363882902160:dw|
d ( common difference ) can be calculated by subtracting two successive numbers in sequence for the Arithmetic Progression common difference should be common ie same otherwise its not in AP
|dw:1363883222149:dw|
plugging in n = 100 in above equation we have the 100th term as 5*100-1 =499 so B is right You got right d00d!