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Describe the vertical asymptote(s) and hole(s) for the graph of y=(x1)(x+3)/(x+3)(x5)
[1:06:17 PM] Akora: asymptote: x = –1 and hole: x = 5
asymptote: x = 5 and hole: x = –3
asymptote: x = –5 and hole: x = 3
asymptotes: x = 5 and x = –3
 one year ago
 one year ago
Describe the vertical asymptote(s) and hole(s) for the graph of y=(x1)(x+3)/(x+3)(x5) [1:06:17 PM] Akora: asymptote: x = –1 and hole: x = 5 asymptote: x = 5 and hole: x = –3 asymptote: x = –5 and hole: x = 3 asymptotes: x = 5 and x = –3
 one year ago
 one year ago

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rajathsbhatBest ResponseYou've already chosen the best response.0
why did you close the last question? It looks like you're pasting the questions from a test.
 one year ago

mamma17Best ResponseYou've already chosen the best response.0
no it aint from a testitis jux i did not neeit any more ani figured it out and copy them from skype cause i am asng some oer fiends as well
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
oh? so what was the answer to the last question?
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
OK that's right. If you're really not cheating, I'm sorry I doubted you.
 one year ago

mamma17Best ResponseYou've already chosen the best response.0
iaint it is a quick checkand idid the lesson jux d not undrsand it
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
\[ y=\frac{(x1)(x+3)}{(x+3)(x5)}\]
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
ok then. This question is exactly like the previous questions. Do the exact same thing.
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
you can cancel the \(x+3\) factor, which means it has a "hole" at \(x=3\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
however you cannot cancel the factor of \(x5\) so it has a vertical asymptote at \(x=5\)
 one year ago
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