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mamma17
 2 years ago
Describe the vertical asymptote(s) and hole(s) for the graph of y=(x1)(x+3)/(x+3)(x5)
[1:06:17 PM] Akora: asymptote: x = –1 and hole: x = 5
asymptote: x = 5 and hole: x = –3
asymptote: x = –5 and hole: x = 3
asymptotes: x = 5 and x = –3
mamma17
 2 years ago
Describe the vertical asymptote(s) and hole(s) for the graph of y=(x1)(x+3)/(x+3)(x5) [1:06:17 PM] Akora: asymptote: x = –1 and hole: x = 5 asymptote: x = 5 and hole: x = –3 asymptote: x = –5 and hole: x = 3 asymptotes: x = 5 and x = –3

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rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.0why did you close the last question? It looks like you're pasting the questions from a test.

mamma17
 2 years ago
Best ResponseYou've already chosen the best response.0no it aint from a testitis jux i did not neeit any more ani figured it out and copy them from skype cause i am asng some oer fiends as well

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.0oh? so what was the answer to the last question?

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.0OK that's right. If you're really not cheating, I'm sorry I doubted you.

mamma17
 2 years ago
Best ResponseYou've already chosen the best response.0iaint it is a quick checkand idid the lesson jux d not undrsand it

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1\[ y=\frac{(x1)(x+3)}{(x+3)(x5)}\]

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.0ok then. This question is exactly like the previous questions. Do the exact same thing.

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1you can cancel the \(x+3\) factor, which means it has a "hole" at \(x=3\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1however you cannot cancel the factor of \(x5\) so it has a vertical asymptote at \(x=5\)
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