## mamma17 2 years ago Describe the vertical asymptote(s) and hole(s) for the graph of y=(x-1)(x+3)/(x+3)(x-5) [1:06:17 PM] Akora: asymptote: x = –1 and hole: x = 5 asymptote: x = 5 and hole: x = –3 asymptote: x = –5 and hole: x = 3 asymptotes: x = 5 and x = –3

1. rajathsbhat

why did you close the last question? It looks like you're pasting the questions from a test.

2. mamma17

no it aint from a testitis jux i did not neeit any more ani figured it out and copy them from skype cause i am asng some oer fiends as well

3. rajathsbhat

oh? so what was the answer to the last question?

4. mamma17

i got A

5. rajathsbhat

OK that's right. If you're really not cheating, I'm sorry I doubted you.

6. mamma17

iaint it is a quick checkand idid the lesson jux d not undrsand it

7. satellite73

$y=\frac{(x-1)(x+3)}{(x+3)(x-5)}$

8. rajathsbhat

ok then. This question is exactly like the previous questions. Do the exact same thing.

9. satellite73

you can cancel the $$x+3$$ factor, which means it has a "hole" at $$x=-3$$

10. satellite73

however you cannot cancel the factor of $$x-5$$ so it has a vertical asymptote at $$x=5$$

11. mamma17

figured it out