anonymous
  • anonymous
an you please show me how to solve an equation like this?! It's not making sense. x² + 6x = –5
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
abb0t
  • abb0t
Add the 5 and set your polynomial to zero.
anonymous
  • anonymous
x² + 6x + 5 = 0?
abb0t
  • abb0t
\[x^2+6x+5 =0\] notice that it's in the form: \[ax^2+bx+c\] to factor, you must find TWO numbers whose product is "c", but the sum of the two terms, result in "b". Does that make sense? It means: n x n = c, but n + n = b

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

abb0t
  • abb0t
where the n's are two constants. meaning numbers - obviously.
anonymous
  • anonymous
Um...still don't get it.
anonymous
  • anonymous
you have to find two numbers whose product is 5 and sum is 6
anonymous
  • anonymous
Oh! Okay!
abb0t
  • abb0t
Yes.
anonymous
  • anonymous
But...that's for factoring right? I need to find the value of x...
anonymous
  • anonymous
yea, you can solve for x by factoring
abb0t
  • abb0t
Yes, to find the value(s) of "x". You need to factor.
anonymous
  • anonymous
or you can use the quadratics formula
anonymous
  • anonymous
Okay...
abb0t
  • abb0t
quadratic formula usually makes the algebra more tedious. It's best if you factor.
anonymous
  • anonymous
Can you guys check my answer once I attempt to figure it out?
anonymous
  • anonymous
sure
abb0t
  • abb0t
Of course.
anonymous
  • anonymous
Okay, I'm coming up with jibberish. Could you walk me through it?
anonymous
  • anonymous
make a list of factors of 5
anonymous
  • anonymous
just 1 and 5
anonymous
  • anonymous
and -1 and -5
anonymous
  • anonymous
yes. so (x + 1)(x + 5) = 0 now you can set those two factors (x + 1 and x + 5) set to 0 and solve for x
anonymous
  • anonymous
right, but you couldn't use -1 and -5 because those don't add up to 6
anonymous
  • anonymous
okay
anonymous
  • anonymous
so solve for x in both x + 5 = 0 and x + 1 = 0 and they will be your answers
anonymous
  • anonymous
-5 and -1?
anonymous
  • anonymous
yes :]
anonymous
  • anonymous
okay thanks!
anonymous
  • anonymous
no problem

Looking for something else?

Not the answer you are looking for? Search for more explanations.