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TSwizzle Group Title

an you please show me how to solve an equation like this?! It's not making sense. x² + 6x = –5

  • one year ago
  • one year ago

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  1. abb0t Group Title
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    Add the 5 and set your polynomial to zero.

    • one year ago
  2. TSwizzle Group Title
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    x² + 6x + 5 = 0?

    • one year ago
  3. abb0t Group Title
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    \[x^2+6x+5 =0\] notice that it's in the form: \[ax^2+bx+c\] to factor, you must find TWO numbers whose product is "c", but the sum of the two terms, result in "b". Does that make sense? It means: n x n = c, but n + n = b

    • one year ago
  4. abb0t Group Title
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    where the n's are two constants. meaning numbers - obviously.

    • one year ago
  5. TSwizzle Group Title
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    Um...still don't get it.

    • one year ago
  6. Khaleesi Group Title
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    you have to find two numbers whose product is 5 and sum is 6

    • one year ago
  7. TSwizzle Group Title
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    Oh! Okay!

    • one year ago
  8. abb0t Group Title
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    Yes.

    • one year ago
  9. TSwizzle Group Title
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    But...that's for factoring right? I need to find the value of x...

    • one year ago
  10. Khaleesi Group Title
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    yea, you can solve for x by factoring

    • one year ago
  11. abb0t Group Title
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    Yes, to find the value(s) of "x". You need to factor.

    • one year ago
  12. Khaleesi Group Title
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    or you can use the quadratics formula

    • one year ago
  13. TSwizzle Group Title
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    Okay...

    • one year ago
  14. abb0t Group Title
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    quadratic formula usually makes the algebra more tedious. It's best if you factor.

    • one year ago
  15. TSwizzle Group Title
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    Can you guys check my answer once I attempt to figure it out?

    • one year ago
  16. Khaleesi Group Title
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    sure

    • one year ago
  17. abb0t Group Title
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    Of course.

    • one year ago
  18. TSwizzle Group Title
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    Okay, I'm coming up with jibberish. Could you walk me through it?

    • one year ago
  19. Khaleesi Group Title
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    make a list of factors of 5

    • one year ago
  20. TSwizzle Group Title
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    just 1 and 5

    • one year ago
  21. TSwizzle Group Title
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    and -1 and -5

    • one year ago
  22. Khaleesi Group Title
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    yes. so (x + 1)(x + 5) = 0 now you can set those two factors (x + 1 and x + 5) set to 0 and solve for x

    • one year ago
  23. Khaleesi Group Title
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    right, but you couldn't use -1 and -5 because those don't add up to 6

    • one year ago
  24. TSwizzle Group Title
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    okay

    • one year ago
  25. Khaleesi Group Title
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    so solve for x in both x + 5 = 0 and x + 1 = 0 and they will be your answers

    • one year ago
  26. TSwizzle Group Title
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    -5 and -1?

    • one year ago
  27. Khaleesi Group Title
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    yes :]

    • one year ago
  28. TSwizzle Group Title
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    okay thanks!

    • one year ago
  29. Khaleesi Group Title
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    no problem

    • one year ago
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