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TSwizzle
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an you please show me how to solve an equation like this?! It's not making sense. x² + 6x = –5
 one year ago
 one year ago
TSwizzle Group Title
an you please show me how to solve an equation like this?! It's not making sense. x² + 6x = –5
 one year ago
 one year ago

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abb0t Group TitleBest ResponseYou've already chosen the best response.2
Add the 5 and set your polynomial to zero.
 one year ago

TSwizzle Group TitleBest ResponseYou've already chosen the best response.1
x² + 6x + 5 = 0?
 one year ago

abb0t Group TitleBest ResponseYou've already chosen the best response.2
\[x^2+6x+5 =0\] notice that it's in the form: \[ax^2+bx+c\] to factor, you must find TWO numbers whose product is "c", but the sum of the two terms, result in "b". Does that make sense? It means: n x n = c, but n + n = b
 one year ago

abb0t Group TitleBest ResponseYou've already chosen the best response.2
where the n's are two constants. meaning numbers  obviously.
 one year ago

TSwizzle Group TitleBest ResponseYou've already chosen the best response.1
Um...still don't get it.
 one year ago

Khaleesi Group TitleBest ResponseYou've already chosen the best response.2
you have to find two numbers whose product is 5 and sum is 6
 one year ago

TSwizzle Group TitleBest ResponseYou've already chosen the best response.1
Oh! Okay!
 one year ago

TSwizzle Group TitleBest ResponseYou've already chosen the best response.1
But...that's for factoring right? I need to find the value of x...
 one year ago

Khaleesi Group TitleBest ResponseYou've already chosen the best response.2
yea, you can solve for x by factoring
 one year ago

abb0t Group TitleBest ResponseYou've already chosen the best response.2
Yes, to find the value(s) of "x". You need to factor.
 one year ago

Khaleesi Group TitleBest ResponseYou've already chosen the best response.2
or you can use the quadratics formula
 one year ago

abb0t Group TitleBest ResponseYou've already chosen the best response.2
quadratic formula usually makes the algebra more tedious. It's best if you factor.
 one year ago

TSwizzle Group TitleBest ResponseYou've already chosen the best response.1
Can you guys check my answer once I attempt to figure it out?
 one year ago

TSwizzle Group TitleBest ResponseYou've already chosen the best response.1
Okay, I'm coming up with jibberish. Could you walk me through it?
 one year ago

Khaleesi Group TitleBest ResponseYou've already chosen the best response.2
make a list of factors of 5
 one year ago

TSwizzle Group TitleBest ResponseYou've already chosen the best response.1
just 1 and 5
 one year ago

TSwizzle Group TitleBest ResponseYou've already chosen the best response.1
and 1 and 5
 one year ago

Khaleesi Group TitleBest ResponseYou've already chosen the best response.2
yes. so (x + 1)(x + 5) = 0 now you can set those two factors (x + 1 and x + 5) set to 0 and solve for x
 one year ago

Khaleesi Group TitleBest ResponseYou've already chosen the best response.2
right, but you couldn't use 1 and 5 because those don't add up to 6
 one year ago

Khaleesi Group TitleBest ResponseYou've already chosen the best response.2
so solve for x in both x + 5 = 0 and x + 1 = 0 and they will be your answers
 one year ago

TSwizzle Group TitleBest ResponseYou've already chosen the best response.1
5 and 1?
 one year ago

TSwizzle Group TitleBest ResponseYou've already chosen the best response.1
okay thanks!
 one year ago

Khaleesi Group TitleBest ResponseYou've already chosen the best response.2
no problem
 one year ago
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