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anonymous
 3 years ago
an you please show me how to solve an equation like this?! It's not making sense. x² + 6x = –5
anonymous
 3 years ago
an you please show me how to solve an equation like this?! It's not making sense. x² + 6x = –5

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abb0t
 3 years ago
Best ResponseYou've already chosen the best response.2Add the 5 and set your polynomial to zero.

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.2\[x^2+6x+5 =0\] notice that it's in the form: \[ax^2+bx+c\] to factor, you must find TWO numbers whose product is "c", but the sum of the two terms, result in "b". Does that make sense? It means: n x n = c, but n + n = b

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.2where the n's are two constants. meaning numbers  obviously.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Um...still don't get it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you have to find two numbers whose product is 5 and sum is 6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But...that's for factoring right? I need to find the value of x...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea, you can solve for x by factoring

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.2Yes, to find the value(s) of "x". You need to factor.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0or you can use the quadratics formula

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.2quadratic formula usually makes the algebra more tedious. It's best if you factor.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Can you guys check my answer once I attempt to figure it out?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, I'm coming up with jibberish. Could you walk me through it?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0make a list of factors of 5

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes. so (x + 1)(x + 5) = 0 now you can set those two factors (x + 1 and x + 5) set to 0 and solve for x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0right, but you couldn't use 1 and 5 because those don't add up to 6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so solve for x in both x + 5 = 0 and x + 1 = 0 and they will be your answers
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