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Add the 5 and set your polynomial to zero.
x² + 6x + 5 = 0?
\[x^2+6x+5 =0\] notice that it's in the form: \[ax^2+bx+c\] to factor, you must find TWO numbers whose product is "c", but the sum of the two terms, result in "b". Does that make sense? It means: n x n = c, but n + n = b
where the n's are two constants. meaning numbers - obviously.
Um...still don't get it.
you have to find two numbers whose product is 5 and sum is 6
But...that's for factoring right? I need to find the value of x...
yea, you can solve for x by factoring
Yes, to find the value(s) of "x". You need to factor.
or you can use the quadratics formula
quadratic formula usually makes the algebra more tedious. It's best if you factor.
Can you guys check my answer once I attempt to figure it out?
Okay, I'm coming up with jibberish. Could you walk me through it?
make a list of factors of 5
just 1 and 5
and -1 and -5
yes. so (x + 1)(x + 5) = 0 now you can set those two factors (x + 1 and x + 5) set to 0 and solve for x
right, but you couldn't use -1 and -5 because those don't add up to 6
so solve for x in both x + 5 = 0 and x + 1 = 0 and they will be your answers
-5 and -1?