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## TSwizzle 2 years ago an you please show me how to solve an equation like this?! It's not making sense. x² + 6x = –5

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1. abb0t

Add the 5 and set your polynomial to zero.

2. TSwizzle

x² + 6x + 5 = 0?

3. abb0t

\[x^2+6x+5 =0\] notice that it's in the form: \[ax^2+bx+c\] to factor, you must find TWO numbers whose product is "c", but the sum of the two terms, result in "b". Does that make sense? It means: n x n = c, but n + n = b

4. abb0t

where the n's are two constants. meaning numbers - obviously.

5. TSwizzle

Um...still don't get it.

6. Khaleesi

you have to find two numbers whose product is 5 and sum is 6

7. TSwizzle

Oh! Okay!

8. abb0t

Yes.

9. TSwizzle

But...that's for factoring right? I need to find the value of x...

10. Khaleesi

yea, you can solve for x by factoring

11. abb0t

Yes, to find the value(s) of "x". You need to factor.

12. Khaleesi

or you can use the quadratics formula

13. TSwizzle

Okay...

14. abb0t

quadratic formula usually makes the algebra more tedious. It's best if you factor.

15. TSwizzle

Can you guys check my answer once I attempt to figure it out?

16. Khaleesi

sure

17. abb0t

Of course.

18. TSwizzle

Okay, I'm coming up with jibberish. Could you walk me through it?

19. Khaleesi

make a list of factors of 5

20. TSwizzle

just 1 and 5

21. TSwizzle

and -1 and -5

22. Khaleesi

yes. so (x + 1)(x + 5) = 0 now you can set those two factors (x + 1 and x + 5) set to 0 and solve for x

23. Khaleesi

right, but you couldn't use -1 and -5 because those don't add up to 6

24. TSwizzle

okay

25. Khaleesi

so solve for x in both x + 5 = 0 and x + 1 = 0 and they will be your answers

26. TSwizzle

-5 and -1?

27. Khaleesi

yes :]

28. TSwizzle

okay thanks!

29. Khaleesi

no problem

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