an you please show me how to solve an equation like this?! It's not making sense. x² + 6x = –5

- anonymous

an you please show me how to solve an equation like this?! It's not making sense. x² + 6x = –5

- chestercat

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- abb0t

Add the 5 and set your polynomial to zero.

- anonymous

x² + 6x + 5 = 0?

- abb0t

\[x^2+6x+5 =0\]
notice that it's in the form: \[ax^2+bx+c\]
to factor, you must find TWO numbers whose product is "c", but the sum of the two terms, result in "b". Does that make sense?
It means: n x n = c, but n + n = b

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## More answers

- abb0t

where the n's are two constants. meaning numbers - obviously.

- anonymous

Um...still don't get it.

- anonymous

you have to find two numbers whose product is 5 and sum is 6

- anonymous

Oh! Okay!

- abb0t

Yes.

- anonymous

But...that's for factoring right? I need to find the value of x...

- anonymous

yea, you can solve for x by factoring

- abb0t

Yes, to find the value(s) of "x". You need to factor.

- anonymous

or you can use the quadratics formula

- anonymous

Okay...

- abb0t

quadratic formula usually makes the algebra more tedious. It's best if you factor.

- anonymous

Can you guys check my answer once I attempt to figure it out?

- anonymous

sure

- abb0t

Of course.

- anonymous

Okay, I'm coming up with jibberish. Could you walk me through it?

- anonymous

make a list of factors of 5

- anonymous

just 1 and 5

- anonymous

and -1 and -5

- anonymous

yes. so (x + 1)(x + 5) = 0
now you can set those two factors (x + 1 and x + 5) set to 0 and solve for x

- anonymous

right, but you couldn't use -1 and -5 because those don't add up to 6

- anonymous

okay

- anonymous

so solve for x in both
x + 5 = 0 and x + 1 = 0
and they will be your answers

- anonymous

-5 and -1?

- anonymous

yes :]

- anonymous

okay thanks!

- anonymous

no problem

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