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raebaby420
What is the solution set of |2x + 4| < 8? x > –6 and x < 2 x > –4 and x < 4 x < –6 and x > 2 x < –4 and x > 4
ill give you a hint, to remove the modulus sign you have to square both sides
thats not right @HawkCrimson
oh really? then u do it :P
it makes no sense me telling u the answers to ur h-w so u can fail ur exam and pass wat counts for nothing
|2x + 4| < 8 2x+4<8 or 2x + 4 >-8 2x<4 or 2x>-12 x<2 or x>-6
@raebaby420 dont listen to him, listen to @Nurali :P