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If you were to use the substitution method to solve the following system, choose the new system of equations that would result if x was isolated in the second equation.
2x + 5y – 2z = –1
x + 3y + z = –2
3x – 2y + 3z = –17
Options:
–y – 4z = 3
–11y = –11
11y = 3
7y + 6z = –11
4x + 11y = –5
–11y = –11
–y = –5
6x + 7y = –11
 one year ago
 one year ago
If you were to use the substitution method to solve the following system, choose the new system of equations that would result if x was isolated in the second equation. 2x + 5y – 2z = –1 x + 3y + z = –2 3x – 2y + 3z = –17 Options: –y – 4z = 3 –11y = –11 11y = 3 7y + 6z = –11 4x + 11y = –5 –11y = –11 –y = –5 6x + 7y = –11
 one year ago
 one year ago

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 one year ago

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