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UmmmHELP

  • 2 years ago

Find the geometric mean of the pair of numbers. 3 and 6

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  1. satellite73
    • 2 years ago
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    same as last one' multiply them , take the square root

  2. electrokid
    • 2 years ago
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    \(c^2=a\times b\) c is the geometrical mean of a and b

  3. satellite73
    • 2 years ago
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    only this time you do not get a prefect square like the last one

  4. electrokid
    • 2 years ago
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    use that or this\[{a\over c}={c\over b}\]

  5. UmmmHELP
    • 2 years ago
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    yeah I did and it came out as 18 then when I got 4.24 but I cant figure out what way to write that out

  6. satellite73
    • 2 years ago
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    \[\sqrt{9\times 3}=\sqrt{9}\times \sqrt{3}=3\sqrt{3}\]

  7. UmmmHELP
    • 2 years ago
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    ^^

  8. satellite73
    • 2 years ago
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    or use a calculator if you want a decimal approximation

  9. UmmmHELP
    • 2 years ago
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    i did use a calculator I am saying I dont know what way to write it out let me show you the options @satellite73

  10. UmmmHELP
    • 2 years ago
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    |dw:1363917149126:dw|

  11. UmmmHELP
    • 2 years ago
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    sorry thats messy

  12. satellite73
    • 2 years ago
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    ok use the option i wrote above

  13. UmmmHELP
    • 2 years ago
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    with the calculator?

  14. satellite73
    • 2 years ago
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    oh damn i messed up

  15. satellite73
    • 2 years ago
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    no i wrote the wrong thing lets take is slow

  16. satellite73
    • 2 years ago
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    \[\sqrt{3\times 6}=\sqrt{18}=\sqrt{9\times 2}=\sqrt{9}\times \sqrt{2}=3\sqrt{2}\]

  17. satellite73
    • 2 years ago
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    final answer is \(3\sqrt{2}\)

  18. UmmmHELP
    • 2 years ago
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    okay thanks

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