## UmmmHELP 2 years ago Find the geometric mean of the pair of numbers. 3 and 6

1. satellite73

same as last one' multiply them , take the square root

2. electrokid

$$c^2=a\times b$$ c is the geometrical mean of a and b

3. satellite73

only this time you do not get a prefect square like the last one

4. electrokid

use that or this${a\over c}={c\over b}$

5. UmmmHELP

yeah I did and it came out as 18 then when I got 4.24 but I cant figure out what way to write that out

6. satellite73

$\sqrt{9\times 3}=\sqrt{9}\times \sqrt{3}=3\sqrt{3}$

7. UmmmHELP

^^

8. satellite73

or use a calculator if you want a decimal approximation

9. UmmmHELP

i did use a calculator I am saying I dont know what way to write it out let me show you the options @satellite73

10. UmmmHELP

|dw:1363917149126:dw|

11. UmmmHELP

sorry thats messy

12. satellite73

ok use the option i wrote above

13. UmmmHELP

with the calculator?

14. satellite73

oh damn i messed up

15. satellite73

no i wrote the wrong thing lets take is slow

16. satellite73

$\sqrt{3\times 6}=\sqrt{18}=\sqrt{9\times 2}=\sqrt{9}\times \sqrt{2}=3\sqrt{2}$

17. satellite73

final answer is $$3\sqrt{2}$$

18. UmmmHELP

okay thanks