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UmmmHELP Group Title

Find the geometric mean of the pair of numbers. 3 and 6

  • one year ago
  • one year ago

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  1. satellite73 Group Title
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    same as last one' multiply them , take the square root

    • one year ago
  2. electrokid Group Title
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    \(c^2=a\times b\) c is the geometrical mean of a and b

    • one year ago
  3. satellite73 Group Title
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    only this time you do not get a prefect square like the last one

    • one year ago
  4. electrokid Group Title
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    use that or this\[{a\over c}={c\over b}\]

    • one year ago
  5. UmmmHELP Group Title
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    yeah I did and it came out as 18 then when I got 4.24 but I cant figure out what way to write that out

    • one year ago
  6. satellite73 Group Title
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    \[\sqrt{9\times 3}=\sqrt{9}\times \sqrt{3}=3\sqrt{3}\]

    • one year ago
  7. UmmmHELP Group Title
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    ^^

    • one year ago
  8. satellite73 Group Title
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    or use a calculator if you want a decimal approximation

    • one year ago
  9. UmmmHELP Group Title
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    i did use a calculator I am saying I dont know what way to write it out let me show you the options @satellite73

    • one year ago
  10. UmmmHELP Group Title
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    |dw:1363917149126:dw|

    • one year ago
  11. UmmmHELP Group Title
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    sorry thats messy

    • one year ago
  12. satellite73 Group Title
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    ok use the option i wrote above

    • one year ago
  13. UmmmHELP Group Title
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    with the calculator?

    • one year ago
  14. satellite73 Group Title
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    oh damn i messed up

    • one year ago
  15. satellite73 Group Title
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    no i wrote the wrong thing lets take is slow

    • one year ago
  16. satellite73 Group Title
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    \[\sqrt{3\times 6}=\sqrt{18}=\sqrt{9\times 2}=\sqrt{9}\times \sqrt{2}=3\sqrt{2}\]

    • one year ago
  17. satellite73 Group Title
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    final answer is \(3\sqrt{2}\)

    • one year ago
  18. UmmmHELP Group Title
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    okay thanks

    • one year ago
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