anonymous
  • anonymous
Find the geometric mean of the pair of numbers. 3 and 6
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
same as last one' multiply them , take the square root
anonymous
  • anonymous
\(c^2=a\times b\) c is the geometrical mean of a and b
anonymous
  • anonymous
only this time you do not get a prefect square like the last one

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anonymous
  • anonymous
use that or this\[{a\over c}={c\over b}\]
anonymous
  • anonymous
yeah I did and it came out as 18 then when I got 4.24 but I cant figure out what way to write that out
anonymous
  • anonymous
\[\sqrt{9\times 3}=\sqrt{9}\times \sqrt{3}=3\sqrt{3}\]
anonymous
  • anonymous
^^
anonymous
  • anonymous
or use a calculator if you want a decimal approximation
anonymous
  • anonymous
i did use a calculator I am saying I dont know what way to write it out let me show you the options @satellite73
anonymous
  • anonymous
|dw:1363917149126:dw|
anonymous
  • anonymous
sorry thats messy
anonymous
  • anonymous
ok use the option i wrote above
anonymous
  • anonymous
with the calculator?
anonymous
  • anonymous
oh damn i messed up
anonymous
  • anonymous
no i wrote the wrong thing lets take is slow
anonymous
  • anonymous
\[\sqrt{3\times 6}=\sqrt{18}=\sqrt{9\times 2}=\sqrt{9}\times \sqrt{2}=3\sqrt{2}\]
anonymous
  • anonymous
final answer is \(3\sqrt{2}\)
anonymous
  • anonymous
okay thanks

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