UmmmHELP
Find the geometric mean of the pair of numbers.
3 and 6



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anonymous
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same as last one'
multiply them , take the square root

electrokid
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\(c^2=a\times b\)
c is the geometrical mean of a and b

anonymous
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only this time you do not get a prefect square like the last one

electrokid
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use that or this\[{a\over c}={c\over b}\]

UmmmHELP
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yeah I did and it came out as 18 then when I got 4.24 but I cant figure out what way to write that out

anonymous
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\[\sqrt{9\times 3}=\sqrt{9}\times \sqrt{3}=3\sqrt{3}\]

UmmmHELP
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^^

anonymous
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or use a calculator if you want a decimal approximation

UmmmHELP
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i did use a calculator I am saying I dont know what way to write it out let me show you the options @satellite73

UmmmHELP
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dw:1363917149126:dw

UmmmHELP
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sorry thats messy

anonymous
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ok use the option i wrote above

UmmmHELP
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with the calculator?

anonymous
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oh damn i messed up

anonymous
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no i wrote the wrong thing
lets take is slow

anonymous
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\[\sqrt{3\times 6}=\sqrt{18}=\sqrt{9\times 2}=\sqrt{9}\times \sqrt{2}=3\sqrt{2}\]

anonymous
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final answer is \(3\sqrt{2}\)

UmmmHELP
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okay thanks