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- anonymous

.

- katieb

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- anonymous

\[(5x^2 + 3x + 4) − (2x^2 − 6x + 3)\]distribute the minus sign and get
\[5x^2 + 3x + 4 -2x^2 + 6x - 3)\]

- anonymous

since you are only asked for B you job is to compute \(3+6\)

- anonymous

yes

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## More answers

- jim_thompson5910

Add up 3x^2 - 9
and 2x + 9
So
(3x^2 - 9) + (2x + 9) = ???

- anonymous

5x^2 ?

- jim_thompson5910

Sorry, I didn't see the first x
Add x, 3x^2 - 9 and 2x+9
(x) + (3x^2 - 9) + (2x + 9)
x + 3x^2 - 9 + 2x + 9
3x^2 + 3x + 0
3x^2 + 3x

- jim_thompson5910

So after adding x, 3x^2 - 9 and 2x + 9, you will get 3x^2 + 3x, which is the total distance covered

- anonymous

soo its 3x^2 + 3x

- anonymous

add them up
\[x+3x^2 - 9+2x + 9\]

- anonymous

yes

- anonymous

thanks!

- anonymous

they really reach for these "word problems" don't they ?

- anonymous

they could have said "add the polynomials"

- anonymous

LOLLL yess they do !! Can you guys do me onee more favor and just double check my work ?

- jim_thompson5910

sure, what do you need to check

- anonymous

ill write the 5 questions and show you my answers

- anonymous

1. Simplify the following expression: (x − 8y) - (2x − 4y)If the final answer is written in the form Ax + By, what is the value of B?
2. Simplify: (4x − 6) − (5x + 1)
3. Simplify: (5x^2 + 3x + 4) + (5x^2 + 5x − 1)
4. Simplify: (4x − 6) + (3x + 6)
& You helped me with the other 2 questions so i just put the ones i did on my own but these were my answers
1. 4y
2. -x-7
3. 10x^2 + 8x + 5
4. 7x+12

- jim_thompson5910

ok one sec

- anonymous

alrighty :] Thanks!!

- jim_thompson5910

#1
the form is form Ax + By
they want the value of B, so the answer cannot be 4y

- jim_thompson5910

besides, -8y + 4y isn't 4y anyway
you lost a sign somewhere

- anonymous

Im bad with my signs /: negatives and positives -.- so confusing

- jim_thompson5910

think of it like this
-8 + 4
is the same as saying
you're 8 dollars in debt, but you paid off $4 of that debt, so you're now 4 dollars in debt

- jim_thompson5910

so that explains how -8 + 4 = -4

- jim_thompson5910

and why -8y + 4y = -4y

- anonymous

so itd be -4?

- jim_thompson5910

B is -4, yep

- anonymous

oki

- jim_thompson5910

# 2 is correct, so congrats on that

- anonymous

thanks :]

- jim_thompson5910

#3 is close

- jim_thompson5910

but not correct fully

- jim_thompson5910

4 + (-1) is NOT 5

- anonymous

-3?

- jim_thompson5910

you have 4 dollars
you add on 1 IOU

- jim_thompson5910

you really have 4-1 = 3 dollars left (after you pay off the IOU)

- jim_thompson5910

so that's why 4 + (-1) = 4 - 1 = 3

- anonymous

oh alright ! i get it now.

- jim_thompson5910

ok great

- jim_thompson5910

# 4 is also incorrect

- anonymous

sorry im blonde it takes a little bit.

- jim_thompson5910

that's ok, just practice practice practice
and hair color is just skin deep...has nothing to do with intelligence

- anonymous

Lol yeah , im guessing #4 is 7x-12

- jim_thompson5910

-6 + 6 = ???

- jim_thompson5910

-6 means you are $6 in debt
add on $6, so you are paying off $6
are you still in debt?

- anonymous

nope itd be zero :o

- jim_thompson5910

yep

- jim_thompson5910

-6+6 = 0

- anonymous

so the answers just 7x?

- jim_thompson5910

so you'd have 7x+0 or just 7x

- jim_thompson5910

you got it

- anonymous

ok aha :]

- jim_thompson5910

just watch out for the signs and try not to forget any

- anonymous

Ill think of the whole dollar thing next time i come to the signs , Thank you so much ! ! :]

- jim_thompson5910

that's how I grasp negatives when I stumble a bit, and you're welcome

- anonymous

Ive always troubled negatives , ive been taking algebra 1 for 3 years now , and havent passed . Im working so much harder now ,

- jim_thompson5910

have you thought of using money terms for negatives before? I'm just curious how your teachers have taught negatives in the past

- anonymous

ive heard of it but it was never enforced.

- jim_thompson5910

I gotcha, so they brought it up (maybe once or twice), but never really stuck to it

- anonymous

nopeeeee

- anonymous

Im trying to finish up my work for next week so im ahead so i can spend my spring break with my younger sister , would you mind helping me with Multiplying monomials?

- jim_thompson5910

sure I can help

- anonymous

Choose the correct simplification of the expression d^3 • d^5.
d
d^15
d^2
d^8

- jim_thompson5910

what did you get

- anonymous

the arrow represents the degree of the monomials incase you didnt already know lol.
and i think its d^15??

- jim_thompson5910

^ means exponents, yes I know
and no it's not d^15

- jim_thompson5910

if you are multiplying expressions with the same base, then you add the corresponding exponents

- jim_thompson5910

example
x^2 times x^3 = x^(2+3) = x^5

- anonymous

Alright that sounds a little better so d^8 ?

- jim_thompson5910

because you can expand out the 'x' terms and you'll see 5 total x terms

- jim_thompson5910

yep d^8

- anonymous

alright you make this so much easier than the lesson lol

- jim_thompson5910

lol glad to hear that

- jim_thompson5910

glad it's finally clicking

- anonymous

Choose the correct simplification of the expression (b^5)^4.
b^9
b^625
b^20
b

- anonymous

b^20 ?

- jim_thompson5910

you got ???

- jim_thompson5910

perfect

- jim_thompson5910

you're a total pro at this

- anonymous

HA i wish!

- jim_thompson5910

you're just not giving yourself enough credit

- anonymous

Choose the correct simplification of the expression (3x)^4.
81x^4
12x^5
81x^5
12x^4

- jim_thompson5910

raise each piece to the 4th power

- anonymous

81x^4 ?

- jim_thompson5910

so you raise 3 to the 4th power to get ____

- jim_thompson5910

yep, you got it

- jim_thompson5910

see you know this stuff

- anonymous

haha slowly but getting it !! :)

- jim_thompson5910

well as long as you get there, that's all that matters

- anonymous

Choose the correct simplification of the expression (x^2y)^2.
x^4y^3
x^6y^6
x^4y^2
xy^4

- jim_thompson5910

what did you get

- anonymous

Havent even tried it yet lol .but im thinking the ^2 on the outside is going to distribute to the ones in the parenthese?

- jim_thompson5910

yes that's one way of thinking about it
basically you raise each part to the 2nd power

- jim_thompson5910

x^2 to the 2nd power ----> x^2 * x^2 = x^(2+2) = x^4

- jim_thompson5910

y to the second power -----> y^2

- jim_thompson5910

or you can multiply the exponents
multiply the outer by each of the inner

- anonymous

so x^4y^2

- jim_thompson5910

yep

- anonymous

:] this isnt so hard

- jim_thompson5910

no, it's not at all
just depends on how much practice you have and how you look at it

- anonymous

Choose the correct simplification of the expression b^5 • b^4.
b
b^9
b^20
b^−1

- jim_thompson5910

you got _____

- anonymous

b^9 ?

- jim_thompson5910

correct

- anonymous

:DD !!

- jim_thompson5910

you add the exponents
I'll brb

- anonymous

3 more ,

- anonymous

ok sounds good.

- jim_thompson5910

no worries I'll be back in a few min and I'll help you with those 3

- anonymous

Okay :D

- jim_thompson5910

ok back

- anonymous

Choose the correct simplification of the expression (d3)^5.
d^8
d^15
d^243
d

- anonymous

d^15 right ?

- jim_thompson5910

correct, assuming you mean (d^3)^5

- anonymous

yes sorry i forgot the ^ x]

- jim_thompson5910

no worries

- anonymous

okay these last 3 .

- anonymous

heres 2 of the 3

##### 1 Attachment

- jim_thompson5910

and you got what for each

- anonymous

How do i simplify them ?

- anonymous

just add the exponents?

- jim_thompson5910

(3d)^3
turns into
27d^3

- jim_thompson5910

so
(3d)^3 * d
becomes
27d^3 * d

- jim_thompson5910

and that becomes what?

- anonymous

um. 27d^4
?

- jim_thompson5910

good

- anonymous

alright i struggled a little bit

- jim_thompson5910

now simplify the other expression

- jim_thompson5910

that's ok, just keep practicing it and it'll come more easily to you

- anonymous

the second one the exponents are just gonna get added to each other right ?

- jim_thompson5910

no, when you square something that has an exponent, you are multiplying the exponents

- jim_thompson5910

ex:
(3x^5)^2 ---> 9x^(5*2) = 9x^(10)

- anonymous

3d^4

- jim_thompson5910

so the exponents are different? or equal?

- anonymous

equal

- jim_thompson5910

so that means you go with C for the first one

- jim_thompson5910

exponents are the same

- anonymous

alright number 8 looks like mumbo jumbo...

- jim_thompson5910

same thing applies to #8, it's just a bit more complicated maybe

- jim_thompson5910

they want you to simplify as much as possible, then compare exponents for expressions 1 and 2

- jim_thompson5910

(2y^2)^3 = 8y^(2*3) = 8y^6

- anonymous

alright .

- jim_thompson5910

(y^9)*(2y^2)^3
turns into
y^9 * 8y^6

- anonymous

what about that y^9

- jim_thompson5910

just added it back in so to speak

- jim_thompson5910

I focused on simplifying (2y^2)^3 first

- jim_thompson5910

then re-introduced the y^9 back in

- anonymous

okay so the first one you just add the like terms now right?

- jim_thompson5910

yep you add the exponents

- anonymous

y^9 * 8y^6 = 9y^15

- jim_thompson5910

the exponent is correct, but that 8 should stay the same

- jim_thompson5910

so it's 8y^15

- jim_thompson5910

silly typo though

- anonymous

alright so 8y^15 for the first one ,

- jim_thompson5910

now simplify the second one using the same steps

- jim_thompson5910

(2y^3)^2 = ???

- anonymous

4y^6

- jim_thompson5910

good

- jim_thompson5910

(9y)(2y^3)^2
becomes
9y*4y^6

- anonymous

13y^6

- jim_thompson5910

you multiply the coefficients out front

- jim_thompson5910

9*4 = 36

- jim_thompson5910

and you add the exponents
1+6 = 7

- anonymous

so 36y^7 ?

- jim_thompson5910

yep

- anonymous

that one was hard lol

- jim_thompson5910

now compare
8y^15 to 36y^7

- jim_thompson5910

its ok, it'll get easier over time

- anonymous

the first ones exponents are greater than

- jim_thompson5910

yep

- anonymous

Alright this is my last one .

- jim_thompson5910

so A

- anonymous

thank god

- jim_thompson5910

lol

- anonymous

Part 1: Explain, using complete sentences, how to simplify the expression below.
Part 2: What is the simplified expression?
(3x^3y^4)(2x^2y^6)

- jim_thompson5910

the coefficients are 3 and 2
what do you do with these?

- anonymous

multiply them

- jim_thompson5910

good

- jim_thompson5910

3 * 2 = 6 is your final coefficient

- jim_thompson5910

now for each variable, you add the corresponding exponents

- anonymous

so 6x^5 ?

- jim_thompson5910

so for the x terms, you add the exponents 3 and 2 to get 3+2 = 5
5 is the final exponent for x

- jim_thompson5910

so far so good, now do y

- anonymous

well y doesnt have any numbers but every variable is equal to 1 , so would it be 2y^10?

- jim_thompson5910

don't worry about the coefficient, that's been taken care of already

- jim_thompson5910

just focus on the exponents for y

- anonymous

so y^10 ?

- jim_thompson5910

they are 4 and 6, they add to 4+6 = 10

- jim_thompson5910

yep

- jim_thompson5910

so all together, we get
6x^5y^10

- anonymous

alright .
so thats the simplied answer?

- jim_thompson5910

it is

- anonymous

that was easier lol

- jim_thompson5910

lol depends on how you look at it i guess

- anonymous

Thank you so much for all your time helping me tonight .

- jim_thompson5910

you're welcome

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