anonymous
  • anonymous
1.A local bank has a debit card that gives a $3 reward each month you use your card for $50 or more in purchaces. Write an equation relating rewards earned,y, to total monthly purchaces, x. Give the domain of this function. 2. A local credit union has a debit card that rewards 3% of your total monthly purchases. Write an equation relating rewards earned,y, to total monthly purchases, x. Give domain of this function.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
the second one is easiest i think you get 3% of your monthly purchases, so if you call your monthly purchases \(x\) then you get \(y=0.03x\)
anonymous
  • anonymous
it has no lower limit, so i would say the domain is \((0,\infty)\) or "positive numbers"
anonymous
  • anonymous
Honestly, any input would be appreciated. I'm totally clueless!

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anonymous
  • anonymous
this is not quite accurate, since you cannot spend say \(\pi\) dollars so maybe the domain is positive integers
anonymous
  • anonymous
how fancy is this math class?
anonymous
  • anonymous
maybe you can get away with saying "positive numbers"
anonymous
  • anonymous
It's just Algebra 1
anonymous
  • anonymous
okay so you probably don't have to be so picky for the second one you can use \(y=0.03x\) and say the domain is positive numbers
anonymous
  • anonymous
for the first one, it is really \[y= \left\{\begin{array}{rcc} 0 & \text{if} & x <50\\ 3& \text{if} & x \geq50 \end{array} \right. \]
anonymous
  • anonymous
but that might be too fancy as well, so maybe you can just say \(y=3\) if \(x\geq50\) or maybe even just say \(y=3\) and the domain is \(x\geq 50\)
anonymous
  • anonymous
Okay, thank you so much!! I've been stuck on math problems all night. I still have 3 more to go :(
anonymous
  • anonymous
are they hard?
anonymous
  • anonymous
go ahead and post, i will look, or just ask here
anonymous
  • anonymous
I'll type it here, if that's alright
anonymous
  • anonymous
go ahead, i will answer if i can
anonymous
  • anonymous
1. Abigail orders a large 2 topping pizza for $14 and a medium 1 topping pizza for $10. If all coats of a medium pizza are 80% of a similar large pizza, find rhe price of a large plain cheese and the cost of each large pizza topping.
anonymous
  • anonymous
costs*
anonymous
  • anonymous
whoa this is going to take a second not too long though
anonymous
  • anonymous
You don't have to do it if you don't want to! I understand.
anonymous
  • anonymous
oh no we can definitely do this for sure
anonymous
  • anonymous
Alrighty, thank you so much.
anonymous
  • anonymous
we can call the price of the topping \(y\) and the price of the large plain pizza \(x\) so the price of the medium plain pizza is \(0.8x\)
anonymous
  • anonymous
Okay
anonymous
  • anonymous
then the first part tells you \[x+2y=14\] and the second part say \[.8x+y=10\]
anonymous
  • anonymous
Right
anonymous
  • anonymous
now before we solve this, i can make a good guess, which is that \(x=10\) and \(y=2\)
anonymous
  • anonymous
because \(10+2\times 2=14\) and \(0.8x\times 10+2=8+2=10\)
anonymous
  • anonymous
i am assuming of course that the toppings for the large and small pizza are the same if they are not the same you cannot solve the problem
anonymous
  • anonymous
Yeah
anonymous
  • anonymous
in any case to solve \[x+2y=14\]\[.8x+y=10\] multiply the second equation by -2 and add you get \[x+2y=14\] \[-1.6x-2y=-20\] \[-.6x=-6\] \[x=-6\div -.6=60\div 6=10\]
anonymous
  • anonymous
so it is right large pizza is $10, medium is $8, toppings are $2
anonymous
  • anonymous
so far so good?
anonymous
  • anonymous
Thank you so much! You make the problems seem so much easier. I might actually get some sleep tonight for school tomorrow!
anonymous
  • anonymous
yw any more or are you done?
anonymous
  • anonymous
I have one more.
anonymous
  • anonymous
It's the hardest one
anonymous
  • anonymous
k
anonymous
  • anonymous
ready?
anonymous
  • anonymous
Nathan wants to go to a hockey game with friends. Tickets are $18, but students can get discounted tickets for $12. They want to spend no more than $80, including $8 for parking. The vehicle they will take can only hold 7 people. Write and graph (it's a regualr coordinate graph) a system of foir inequalities modeling their possible ticket purchases. Let x= number of student tickets and y= number of regular tickets
anonymous
  • anonymous
one thing we know is that \(x+y\leq 7\)
anonymous
  • anonymous
because at most 7 people can go
anonymous
  • anonymous
we also know that they are going to pay $8 for parking, leaving \(80-8=\$72\) for tickets and so \(12x+18y\leq 72\)
anonymous
  • anonymous
i think the other two inequalities are the easy ones, both \(x\geq 0\) and \(y\geq 0\) which just means you are in quadrant 1
anonymous
  • anonymous
can you graph \(x+y=7\)?
anonymous
  • anonymous
Uh, no :/
anonymous
  • anonymous
|dw:1363921714846:dw|
anonymous
  • anonymous
if \(x=0\) you get \(y=7\) so \((0,7)\) is on the graph, and similarly \((7,0)\) is on the graph plot the points, connect the dots
anonymous
  • anonymous
you got it from the picture?
anonymous
  • anonymous
I can't see your drawing because I'm on my phone, I can't access a computer.
anonymous
  • anonymous
I know how to graph points, so I should be fine
anonymous
  • anonymous
ooh ok
anonymous
  • anonymous
Whatt do I do next?
anonymous
  • anonymous
the line \(12x+18y=72\) contains the points \((0,4)\) and \((6,0)\) so plot those points as well and connect the dots
anonymous
  • anonymous
then shade everything in quadrant 1, and below those two lines
anonymous
  • anonymous
i obviously cannot draw it here for you to see, but that is what you have to do
anonymous
  • anonymous
Yes, I understand
anonymous
  • anonymous
then i guess you are done any point that is shaded in the picture is possible
anonymous
  • anonymous
Ok, sweet. Thank you very much for all your time and help. Have a nice night! :)
anonymous
  • anonymous
you too

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