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1.A local bank has a debit card that gives a $3 reward each month you use your card for $50 or more in purchaces. Write an equation relating rewards earned,y, to total monthly purchaces, x. Give the domain of this function. 2. A local credit union has a debit card that rewards 3% of your total monthly purchases. Write an equation relating rewards earned,y, to total monthly purchases, x. Give domain of this function.

Mathematics
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the second one is easiest i think you get 3% of your monthly purchases, so if you call your monthly purchases \(x\) then you get \(y=0.03x\)
it has no lower limit, so i would say the domain is \((0,\infty)\) or "positive numbers"
Honestly, any input would be appreciated. I'm totally clueless!

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Other answers:

this is not quite accurate, since you cannot spend say \(\pi\) dollars so maybe the domain is positive integers
how fancy is this math class?
maybe you can get away with saying "positive numbers"
It's just Algebra 1
okay so you probably don't have to be so picky for the second one you can use \(y=0.03x\) and say the domain is positive numbers
for the first one, it is really \[y= \left\{\begin{array}{rcc} 0 & \text{if} & x <50\\ 3& \text{if} & x \geq50 \end{array} \right. \]
but that might be too fancy as well, so maybe you can just say \(y=3\) if \(x\geq50\) or maybe even just say \(y=3\) and the domain is \(x\geq 50\)
Okay, thank you so much!! I've been stuck on math problems all night. I still have 3 more to go :(
are they hard?
go ahead and post, i will look, or just ask here
I'll type it here, if that's alright
go ahead, i will answer if i can
1. Abigail orders a large 2 topping pizza for $14 and a medium 1 topping pizza for $10. If all coats of a medium pizza are 80% of a similar large pizza, find rhe price of a large plain cheese and the cost of each large pizza topping.
costs*
whoa this is going to take a second not too long though
You don't have to do it if you don't want to! I understand.
oh no we can definitely do this for sure
Alrighty, thank you so much.
we can call the price of the topping \(y\) and the price of the large plain pizza \(x\) so the price of the medium plain pizza is \(0.8x\)
Okay
then the first part tells you \[x+2y=14\] and the second part say \[.8x+y=10\]
Right
now before we solve this, i can make a good guess, which is that \(x=10\) and \(y=2\)
because \(10+2\times 2=14\) and \(0.8x\times 10+2=8+2=10\)
i am assuming of course that the toppings for the large and small pizza are the same if they are not the same you cannot solve the problem
Yeah
in any case to solve \[x+2y=14\]\[.8x+y=10\] multiply the second equation by -2 and add you get \[x+2y=14\] \[-1.6x-2y=-20\] \[-.6x=-6\] \[x=-6\div -.6=60\div 6=10\]
so it is right large pizza is $10, medium is $8, toppings are $2
so far so good?
Thank you so much! You make the problems seem so much easier. I might actually get some sleep tonight for school tomorrow!
yw any more or are you done?
I have one more.
It's the hardest one
k
ready?
Nathan wants to go to a hockey game with friends. Tickets are $18, but students can get discounted tickets for $12. They want to spend no more than $80, including $8 for parking. The vehicle they will take can only hold 7 people. Write and graph (it's a regualr coordinate graph) a system of foir inequalities modeling their possible ticket purchases. Let x= number of student tickets and y= number of regular tickets
one thing we know is that \(x+y\leq 7\)
because at most 7 people can go
we also know that they are going to pay $8 for parking, leaving \(80-8=\$72\) for tickets and so \(12x+18y\leq 72\)
i think the other two inequalities are the easy ones, both \(x\geq 0\) and \(y\geq 0\) which just means you are in quadrant 1
can you graph \(x+y=7\)?
Uh, no :/
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if \(x=0\) you get \(y=7\) so \((0,7)\) is on the graph, and similarly \((7,0)\) is on the graph plot the points, connect the dots
you got it from the picture?
I can't see your drawing because I'm on my phone, I can't access a computer.
I know how to graph points, so I should be fine
ooh ok
Whatt do I do next?
the line \(12x+18y=72\) contains the points \((0,4)\) and \((6,0)\) so plot those points as well and connect the dots
then shade everything in quadrant 1, and below those two lines
i obviously cannot draw it here for you to see, but that is what you have to do
Yes, I understand
then i guess you are done any point that is shaded in the picture is possible
Ok, sweet. Thank you very much for all your time and help. Have a nice night! :)
you too

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