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satellite73Best ResponseYou've already chosen the best response.1
\[xy=4\] and i guess \(x=x(t)\) and \(y=y(t)\) i.e. they are both functions of \(t\) so via the product rule you get \[x'(t)y+y'(t)x=0\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
it is easy to write \(x'\) than \(\frac{dx}{dt}\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
now if \(x=8\) then since \(xy=4\) you know \(y=\frac{1}{2}\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
and you are told \(x'=10\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
solve \[x'(t)y+y'(t)x=0\] which is now \[10\times \frac{1}{2}+y'\times 8=0\] for \(y'\)
 one year ago
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