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mathavraj

  • one year ago

"for a given phase shift the higher is the frequency, the smaller is the required time shift"...please explain this statement..is this in any indirect way related to doppler's law?

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  1. Vincent-Lyon.Fr
    • one year ago
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    Interferences? phase shift \(\Delta \phi\) is to \(2\pi\) what time shift \(\Delta \tau\) is to time period \(T\) Hence \(\Delta \tau=\Delta \phi\times T/2\pi=\Delta \phi /2\pi\nu\) You can see that for a given \(\Delta \phi\) , \(\Delta \tau\) is inversely proportional to frequency \(\nu\).

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