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"for a given phase shift the
higher is the frequency, the smaller is the required time shift"...please explain this statement..is this in any indirect way related to doppler's law?
 one year ago
 one year ago
"for a given phase shift the higher is the frequency, the smaller is the required time shift"...please explain this statement..is this in any indirect way related to doppler's law?
 one year ago
 one year ago

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VincentLyon.FrBest ResponseYou've already chosen the best response.0
Interferences? phase shift \(\Delta \phi\) is to \(2\pi\) what time shift \(\Delta \tau\) is to time period \(T\) Hence \(\Delta \tau=\Delta \phi\times T/2\pi=\Delta \phi /2\pi\nu\) You can see that for a given \(\Delta \phi\) , \(\Delta \tau\) is inversely proportional to frequency \(\nu\).
 one year ago
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