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@satellite73 can u help please?

since the point is \((0,0)\) the equation of the line will be \(y=3x\)

ok so find the derivative of sin 3x right?

yes

Ok so i got 3cos(3x)

yes
now evaluate at \(x=0\) to find your slope

ok i got 3

yes

that is the slope of your line

okay so now i have to use the point slop formula?

yes

but the point is \((0,0)\) so it is just \(y=3x\)

okay so what do i do next?

you are done

okay

linear approximation of f(x) at x=x0:
\[f(x)=f(x_0)+(x-x_0)f'(x_0)\]

you can use this way too. (notice the resemblance to equation of line)