A community for students.
Here's the question you clicked on:
 0 viewing
DeadShot
 2 years ago
What is the simplified form of x plus 3 over x squared minus x minus 12 • x minus 4 over x squared minus 8x plus 16 ?
DeadShot
 2 years ago
What is the simplified form of x plus 3 over x squared minus x minus 12 • x minus 4 over x squared minus 8x plus 16 ?

This Question is Closed

DeadShot
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ x+3 }{ x^2x12 }*\frac{ x4 }{ x^28x+16 }\]

SheldonEinstein
 2 years ago
Best ResponseYou've already chosen the best response.2First you need to factorize both denominators. i would show you how to factorize the denominator, I would take \(x^2  x 12\) as the example and then you have to proceed yourself.

SheldonEinstein
 2 years ago
Best ResponseYou've already chosen the best response.2I have \(x^2  x  12\) \( x^2 + 3x  4x 12\) = \(x(x+3)  4(x+3)\) \((x4)(x+3)\) This is how I factorized \(x^2x12\) by using "middle term splitting" method. Similarly, factorize \(x^2  8x + 16\) by splitting 8x into 4x and 4x : \(x^2  4x 4x + 16\) and then do the proceedings.

SheldonEinstein
 2 years ago
Best ResponseYou've already chosen the best response.2You will have then : \(\cfrac{x+3}{(x4)(x+3)} \times \cfrac{(x4)}{x^28x+16}\) \(\cfrac{(x+3)(x4)}{(x4)(x+3)(x^28x+16)}\) \(\cfrac{\cancel{(x+3)(x4)}}{\cancel{(x4)(x+3)} (x^28x+16)}\) \(\cfrac{1}{x^28x+16}\) put the factorized form of \(x^28x+16\) on the place of it and you will get the required answer. I hope it helped. Post here if you get any problem Do not forget to tell what you get.. best of luck!

DeadShot
 2 years ago
Best ResponseYou've already chosen the best response.1I got \[\frac{ 1 }{ (x  4)^2 }\]is that correct?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.