The dimensions of a smaller rectangle are 3 ft by 9 ft. The dimensions of a larger rectangle are 5 ft by 15 ft. Find the ratio of the area of the smaller rectangle to the area of the larger rectangle.

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The dimensions of a smaller rectangle are 3 ft by 9 ft. The dimensions of a larger rectangle are 5 ft by 15 ft. Find the ratio of the area of the smaller rectangle to the area of the larger rectangle.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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First of all find the area of the smaller rectangle. Do you know the formula for it?
lets say area of smaller rectangle is A1 and larger A2, now the ratio of areas is given as follows \[\frac{ A _{1}}{ A _{2} }=\frac{ 3*9 }{ 5*15 }=\frac{ 9 }{ 25 }\]
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Find the area of smaller rectangle first by putting length = 3 ft. and breadth = 9 ft. then find the area of larger rectangle. You can find the ratios of the areas by : \(\cfrac{\textbf{Area of smaller rectangle}}{\textbf{Area of Larger rectangle}} = \textbf{Required ratio}\)
Do post here, what you get @ohnaw
i forgot i had this question up.. i forgot that acct info.. @SheldonEinstein ... thank yall @ghazi

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