Gabylovesyou
  • Gabylovesyou
5x^2 − 2x − 7 how do i factor that?
Mathematics
jamiebookeater
  • jamiebookeater
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ash2326
  • ash2326
@Gabylovesyou did you try this?
Gabylovesyou
  • Gabylovesyou
@ash2326 no... i dont know how to lol
ash2326
  • ash2326
I think you have asked quite a few questions similar to this.

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anonymous
  • anonymous
GABY?!
Gabylovesyou
  • Gabylovesyou
WHAT?! lol
Gabylovesyou
  • Gabylovesyou
@ash2326 can you help me with this one?
Gabylovesyou
  • Gabylovesyou
@tywan wrong person lol :p
anonymous
  • anonymous
Dont use FOIL, I can't believe FOIL is even used these days. Just "break up" the middle term
anonymous
  • anonymous
|dw:1363899270806:dw|
Gabylovesyou
  • Gabylovesyou
how did u get 5x^2 + 5x - 7x -7 ?
anonymous
  • anonymous
what you do is break up the middle number into 2 numbers, the combinations can be infinite but among them, you choose 2 numbers which are multiples of each number at the corners
anonymous
  • anonymous
hope that helped
anonymous
  • anonymous
\[5x^2+5x-7x-7=0, 5x(x+1)-7(x+1)=0, (5x-7)(x+1)=0\] they way your gona split middle term should give the product of two end terms , like 7*5= 35 , so were gona split middle term in a way so that we can get 35, thats y we wrote -2x=-7x+5x
anonymous
  • anonymous
take 5*7= will be 35 -7+5=-2 5x^2+5x-7x+7 group it 5x^2+5x common is 5x(x+1) -7x+7 common is 7 but pull out -1 -7(x+1) (5x-7)(x+1)

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