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Gabylovesyou

  • 2 years ago

5x^2 − 2x − 7 how do i factor that?

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  1. ash2326
    • 2 years ago
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    @Gabylovesyou did you try this?

  2. Gabylovesyou
    • 2 years ago
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    @ash2326 no... i dont know how to lol

  3. ash2326
    • 2 years ago
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    I think you have asked quite a few questions similar to this.

  4. tywan
    • 2 years ago
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    GABY?!

  5. Gabylovesyou
    • 2 years ago
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    WHAT?! lol

  6. Gabylovesyou
    • 2 years ago
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    @ash2326 can you help me with this one?

  7. Gabylovesyou
    • 2 years ago
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    @tywan wrong person lol :p

  8. Luis_Rivera
    • 2 years ago
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    Dont use FOIL, I can't believe FOIL is even used these days. Just "break up" the middle term

  9. Luis_Rivera
    • 2 years ago
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    |dw:1363899270806:dw|

  10. Gabylovesyou
    • 2 years ago
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    how did u get 5x^2 + 5x - 7x -7 ?

  11. Luis_Rivera
    • 2 years ago
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    what you do is break up the middle number into 2 numbers, the combinations can be infinite but among them, you choose 2 numbers which are multiples of each number at the corners

  12. Luis_Rivera
    • 2 years ago
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    hope that helped

  13. itsmylife
    • 2 years ago
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    \[5x^2+5x-7x-7=0, 5x(x+1)-7(x+1)=0, (5x-7)(x+1)=0\] they way your gona split middle term should give the product of two end terms , like 7*5= 35 , so were gona split middle term in a way so that we can get 35, thats y we wrote -2x=-7x+5x

  14. seiga
    • 2 years ago
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    take 5*7= will be 35 -7+5=-2 5x^2+5x-7x+7 group it 5x^2+5x common is 5x(x+1) -7x+7 common is 7 but pull out -1 -7(x+1) (5x-7)(x+1)

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