What is the solution for this system of linear equations? please explain!! y=x-8 y=8x-71

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What is the solution for this system of linear equations? please explain!! y=x-8 y=8x-71

Mathematics
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set them equal to eachother, you will end up with x-8 = 8x -71, solve for x
then what do you do? im confused?
start by adding 71 to both sides

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Other answers:

x=63?
close, divide by the coefficient of the x
whats the coefficient?
7
so I have 8x-71=1x=8 explain to me what I do from here? I subtract 71 from both sides here?
i would start by subtracting \(x\) from both sides, to put all the terms with \(x\) on the left
in other words get \(7x-71=-8\)
solution of a set of equation means |dw:1364000497143:dw| find the point P(x,y) which satisfies all the equations.
then add 71 to both sides to get \[7x=63\] and finally divide both sides by \&\)
that, is , finally divide both sides by \(7\)
so the answer for x=9?
correct.
so how would I find y now since I know x?
you replace \(x\) by \(9\) in either equation
wait, is y=1?
yes
\[y=x-8\] \[y=9-8=1\]
omg thank you so much! you're amazing!
set them side by side like this: x-8=8x-71 subtract -8 on both sides and add 8 to both sides now you should get -7x=-63
yw (if you meant me, if not, then yw from everyone )
now plug byour answer back into the first equation to get y

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