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set them equal to eachother, you will end up with x-8 = 8x -71, solve for x

then what do you do? im confused?

start by adding 71 to both sides

x=63?

close, divide by the coefficient of the x

whats the coefficient?

so I have 8x-71=1x=8
explain to me what I do from here?
I subtract 71 from both sides here?

i would start by subtracting \(x\) from both sides, to put all the terms with \(x\) on the left

in other words get \(7x-71=-8\)

then add 71 to both sides to get
\[7x=63\] and finally divide both sides by \&\)

that, is , finally divide both sides by \(7\)

so the answer for x=9?

correct.

so how would I find y now since I know x?

you replace \(x\) by \(9\) in either equation

wait, is y=1?

yes

\[y=x-8\]
\[y=9-8=1\]

omg thank you so much! you're amazing!

yw (if you meant me, if not, then yw from everyone )

now plug byour answer back into the first equation to get y