Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

happykiddo

  • 3 years ago

Which of the following is a solution to the equation x^2 – 6x + 5 = 0? A. x = -5 B. x = -1 C. x = 1/5 D. x = 5

  • This Question is Closed
  1. happykiddo
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i know its D but how to get i dont know

  2. yoyointegrals
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    break it up into (x-1)(x-5) = 0

  3. yoyointegrals
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    solve for x-1 = 0 and x-5=0

  4. happykiddo
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i know i factored but it gives me two solutions 5 and 1

  5. happykiddo
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    there is only supposed to be one (which is 5), as shown on the answer key

  6. precal
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    2nd power means you are looking for 2 solutions. Which implies one is given and not all......

  7. happykiddo
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    could you give me an example of what you mean precal

  8. precal
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1364226013438:dw|this quadratic has 2 solutions because the function crossed the x axis in 2 places. your multiple choice only listed one of the 2 solutions

  9. happykiddo
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay thanks precal : )

  10. precal
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yw

  11. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy