What is the general formula to factoring x^n+1 where n is a natural number?
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
just a general thought question, also I am going to bed so you might want to disregard this one
but bonus points if you can use full mathematical symbols!!! it'd be such a great learning experience for me :)
Not the answer you are looking for? Search for more explanations.
also, some sort of hint for the dedicated, you could probably reformulate this problem in terms of the nth roots of unity
It's easier to think of it as \[
x^n = -1
\]So we have two cases. Either \(n\) is odd, and the roots are just \(-1\) or \(n\) is even, and the roots are \(\pm i\)
@wio , so starting with that I could probably write the solution in terms of 2 sigmas (one for n is odd and one for n is even)?
I think I"l try to do this one tomorrow actually. GOod practice for someone like me.
or Pis, cause of the repeated multiplication
Depends on how you want to factor it. It does have roots that are complex, but it doesn't have real roots, so you can't factorize it.